To make the inequality, we will use the ≥ sign to determine how many more tickets we will need. Before we write the inequality, let's see how much money was already made by the present tickets. 70 x 9.50 = $665.
We can write the inequality as $665 + $9.50t ≥ $1000 where t is the number of tickets sold. Now we can solve
$665 + $9.50t ≥ $1000, subtract 665
$9.50t ≥ $335. Now isolate the t by divide 9.50 to both sides
t ≥ 35.26 which we can round up to 36 because you cant sell 35.26 tickets.
So you need at least 36 more tickets to earn at least $1000
Answer:
There are 199 pairs of consecutive natural numbers whose product is less than 40000.
Step-by-step explanation:
We notice that such statement can be translated into this inequation:

Now we solve this inequation to the highest value of
that satisfy the inequation:


The Quadratic Formula shows that roots are:






Only the first root is valid source to determine the highest possible value of
, which is
. Each natural number represents an element itself and each pair represents an element as a function of the lowest consecutive natural number. Hence, there are 199 pairs of consecutive natural numbers whose product is less than 40000.
R² - 6r - 8 = 0
r² = 7.12
r = -1.12
For this case we have that the equation of a line of the slope-intersection form is given by:

Where:
m: It's the slope
b: It is the cut-off point with the y axis
In this case we have the following data:

Then, the equation is of the form:

We find "b" replacing the point:

Thus, the equation is:

Answer:
