3 consecutive odd integers : x, x + 2, x + 4
3(x + x + 2 + x + 4) = x(x + 2) + 24
3(3x + 6) = x^2 + 2x + 24
9x + 18 = x^2 + 2x + 24
x^2 - 7x + 6 = 0
(x - 1)(x - 6) = 0
x - 1 = 0
x = 1
x - 6 = 0
x = 6 (this will not work...it is even)
ur 3 consecutive odd integers :
x = 1
x + 2 = 1 + 2 = 3
x + 4 = 1 + 4 = 5
3rd answer always solve parenthesis first use PEMDAS
Nearest hundred thousand: 400,000
Nearest thousand: 422,000
hope this helps x
Answer:
Step-by-step explanation:
You need to bring the -5 to the left side.
x^2-6x+5=0
Wat two numbers, when multiplied equal to +5? Also when added make the middle term or -6? -5 and -1.
(x-1)(x-5) The x^2 would factor to be x*x
So the answer is the (x-1)(x-5)
