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3 years ago

6

Which of these is the algebraic expression for the verbal expression "ten times the difference of a number and twelve?"

1 answer:

fredd [130]3 years ago

5 0

The answer is, A. 10(x - 12)

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What do I do in order to solve this problem?

DENIUS [597]

Answer:

Step-by-step explanation:

There are two LEGS in a RIGHT TRIANGLE. In order to find the HYPOTENUSE, you must find the OPERATION. Then ROUND.

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2 years ago

How do you solve (x+4)2 ?

Savatey [412]

Answer:

find the value of x or do

(4x)2

Step-by-step explanation:

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3 years ago

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find the measure of the arc or angle indicated. assume that lines which appear tangent are tangent

Serjik [45]

Answer:

Option (1)

Step-by-step explanation:

By the property of alternate segment theorem,

"Angle formed between the tangent and the chord in a circle measures the half of the measure of the intercepted arc"

m(∠EFG) = $\frac{1}{2}$ × m(minor arc FG)

minor arc FG = 2m(∠EFG)

= 2(76°)

= 152°

Therefore, Option (1) will be the correct option.

7 0

2 years ago

Which expression is equivalent to 4(7 + 8)?<br><br>A) 11+8<br>B) 11+12<br>C) 28+12<br>D) 28+32

andreev551 [17]

To do this we take the outlier off the parenthesis (the 4) and multiply it by the two numbers inside the parenthesis...

4*7 + 4*8

28+32

7 0

3 years ago

Read 2 more answers

A series of three? separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers. Each

Nadya [2.5K]

Answer:

$312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$

Step-by-step explanation:

We have been given that a series of 3 separate, adjacent tunnels is constructed through a mountain. Its length is approximately 25 kilometers.

Each of the three tunnels is shaped like a half-cylinder with a radius of 5 meters.

Since we know that volume of a semicircular or a half cylinder is half the volume of a circular cylinder.

$\text{Volume of a semicircular cylinder}=\frac{\pi r^2h}{2}$ , where,

r = Radius of cylinder,

h = height of the cylinder.

Upon substituting our given values in volume formula we will get,

$\text{Volume of a semicircular cylinder}=\frac{\pi (5\text{ km})^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*25\text{ km}^2*25\text{ km}}{2}$

$\text{Volume of a semicircular cylinder}=\frac{\pi*625\text{ km}^3}{2}$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=\pi*312.5\text{ km}^3$

$\text{Volume of a semicircular cylinder}=981.74770\text{ km}^3$

Therefore, the volume of earth removed to build the three tunnels is $312.5\pi \text{ km}^3\approx 981.75\text{ km}^3$ .

4 0

3 years ago