The one circled help please
1 answer:
The graph is shown in the attached image.
You can either use a graphing tool, or get points manually (get the corresponding value of y for each x) and then graph these points.
The standard form of the equation of the circle is:
(x-h)² + (y-k)² = r²
where:
(h,k) represent the coordinates of the center of the circle
r represents the radius of the circle
Now, the given equation is:
x² = -y² + 16
Putting this equation in the standard form:
(x-0)² + (y-0)² = (4)²
Comparing the given equation with the standard form, we will find that:
The center of the circle is at the origin (0,0)
The radius of the circle is 4 units
Hope this helps :)
You can either use a graphing tool, or get points manually (get the corresponding value of y for each x) and then graph these points.
The standard form of the equation of the circle is:
(x-h)² + (y-k)² = r²
where:
(h,k) represent the coordinates of the center of the circle
r represents the radius of the circle
Now, the given equation is:
x² = -y² + 16
Putting this equation in the standard form:
(x-0)² + (y-0)² = (4)²
Comparing the given equation with the standard form, we will find that:
The center of the circle is at the origin (0,0)
The radius of the circle is 4 units
Hope this helps :)
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