Math help,, please help !

Which table shows a function that is decreasing only over the interval (–1, ∞)? A 2-column table with 6 rows. The first column i

Lemur [1.5K]

Answer:

B. f(x) ≤ 0 over the interval [0, 2]. D.f(x) > 0 over the interval (–2, 0). E.f(x) ≥ 0 over the interval [2, ).

Step-by-step explanation:

Those are the 3 answers. Just did it on edge.

8 0

3 years ago

Lines l and m are parallel. Use the diagram to determine the measure of ∠3.

Pavlova-9 [17]

Answer:

∠3 is 70°

Step-by-step explanation:

∠1 is 50° since it is across from another 50° angle

and then you use the equation x+25+2x+50=180 to find x

x then equals 35°

you then use the alternate interior angle theorem to say that ∠3 is 2x, or 70°

5 0

3 years ago

Find the value of x a. 7.5 b. 6 c. 10 d. 8

Radda [10]

B.6 because the length is equal to the length of the other 6

7 0

3 years ago

x^2-y=7 and y-5x=-11 The system of equations above has two solutions. The solution in Quadrant 1 is (A,B) and the solution in Qu

dimaraw [331]

By solving the system of equations, we can see that the solutions are:

(A, B) = (4, 9)

(C, D) = (1, -6).

<h3>How to solve the system of equations?</h3>

Here we have the following system of equations:

x^2 - y = 7

y - 5x = -11

If we isolate the variable y in both equations, we get:

y = x^2 - 7

y = -11 + 5x

Now we can equate these two to get:

x^2 - 7 = -11 + 5x

now we have a quadratic equation, this can be rewritten as:

x^2 - 7 + 11 - 5x = 0

x^2 - 5x + 4 = 0

Using the quadratic formula, we will see that the solutions are:

$x = \frac{5 \pm \sqrt{(-5)^2 - 4*1*(4)} }{2*1}$

Solving that we get:

$x = \frac{5 \pm \sqrt{(9} }{2} \\\\x = \frac{5 \pm 3}{2}$

So the two solutions for x are:

x = (5 + 3)/2 = 4

x = (5 - 3)/2 = 1

Evaluating the second equation in these x-values we get:

y = -11 + 5*4 = -11 + 20 = 9

y = -11 + 5*1 = -6

Then we have the coordinate pairs: (4, 9) (on the first quadrant) and (1, -6) on the fourth quadrant.

Learn more about systems of equations:

brainly.com/question/13729904

#SPJ1

8 0

1 year ago

NEED THE ANSWER ASAP, PLEASE HELP!! What are the coordinates of the focus of the parabola?

qwelly [4]

Answer:

Vertex is (-8, 4) not one of the answers offered!

Step-by-step explanation:

Factor -1/8 out of the first two terms. Leave a space inside parentheses in which to add a number.

$y=-\frac{1}{8}(x^2 + 16x + \text{-----})-4$

Complete the square by squaring half the coefficient of x and adding it in the space.

$(\frac{16}{2})^2=64$

Add 64 in the space you made, then compensate for that at the end of the expression by subtracting $-\frac{1}{8}(64)=-8$

$y=-\frac{1}{8}(x^2+16x+64)-4+8\\y=-\frac{1}{8}(x+8)^2+4$

The x-coordinate of the vertex is the opposite of +8, the number inside the parentheses. The y-coordinate of the vertex is the number at the end of the expression.

V(-8, 4)

8 0

3 years ago