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3 years ago

15

Using the graph of f(x) and g(x), where g(x) = f(k⋅x), determine the value of k. Graph of two lines. f of x passes through 1, 2

and 2, 5, and g of x passes through one half, 2 and 1, 5.

1 answer:

disa [49]3 years ago

5 0

It’s 1,2 f(x) and gf of c

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I need help please either discord me the answer at F4deG0d#0988 or do it on here cause this is important.

algol13

Answer:

x= 12.5

So

2x = 25

4x = 50

6x = 75

Step-by-step explanation:

line CG is 180 degrees, so 12x + 30 = 180

x = 12.5

7 0

2 years ago

(5x+1)(5x-1) combine terms

Alinara [238K]

Answer:

25x^2 -1

Step-by-step explanation:

If you multiply parentheses:

(5x*5x) + (5x*-1) + (1*5x) + (1*-1)

25x^2 - 5x + 5x -1

25x^2 -1

A simpler way is to memorize this formula

(Square1 - square2)= (sqrt of square1- sqrt of square2)*(sqrt of square1 + sqrt of sqaure2)

5 0

3 years ago

The width of a rectangle is (5x + 2) inches and the length is (6x − 7) inches. Find the area of the rectangle.

Degger [83]

Answer:

<h2><u><em>30x² − 23x − 14</em></u></h2>

Explanation:

Area = Length · Width

Length: (6x - 7)

Width: (5x + 2)

Create An Equation

(6x - 7) (5x + 2)

= (6x + −7)(5x + 2)

(6x)(5x) + (6x)(2) + (−7)(5x) + (−7)(2)

= 30x² + 12x − 35x − 14

30x² − 23x − 14

- PNW

7 0

2 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

7 0

2 years ago

Read 2 more answers

Name the property of multiplication illustrated<br><br> 112 X 1 = 112

Nat2105 [25]

Answer:

Identity property

Step-by-step explanation: because the product of any number and one is that number

4 0

2 years ago