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AnnZ [28]
3 years ago
12

(20 points)Solve the equation cos x = sin (x + 22)

Mathematics
1 answer:
Law Incorporation [45]3 years ago
7 0

Answer:

\bold{x = 34^\circ}

Step-by-step explanation:

Given:

cos x = sin (x + 22^\circ)

To solve:

The given equation.

Solution:

First of all, let us consider an important property of sine and cosine.

sin(90^\circ-\theta )=cos\theta

OR

cos(90^\circ-\theta )=sin\theta

We can apply above property to solve for x as per given equation.

cos x = sin (x + 22^\circ)

Changing cosx to sine form:

cosx=sin(90^\circ-x)

cosx=sin(90^\circ-x) = sin(x+22^\circ)

\therefore 90^\circ-x=x+22^\circ\\\Rightarrow 90^\circ-22^\circ=x+x\\\Rightarrow 2x=68^\circ\\\Rightarrow \bold{x = 34^\circ}

So, solution to the equation cos x = sin (x + 22^\circ) is:

\bold{x = 34^\circ}

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The Law of Cosines is always preferable when there's a choice.  There will be two triangle angles (between 0 and 180 degrees) that share the same sine (supplementary angles) but the value of the cosine uniquely determines a triangle angle.

To find a missing side, we use the Law of Cosines when we know two sides and their included angle.   We use the Law of Sines when we know another side and all the triangle angles.  (We only need to know two of three to know all three, because they add to 180.  There are only two degrees of freedom, to answer a different question I just did.

<span>2.An archway will be constructed over a walkway. A piece of wood will need to be curved to match a parabola. Explain to Maurice how to find the equation of the parabola given the focal point and the directrix.
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The points (x,y) on the parabola are equidistant from the line to the point.  Since the distances are equal so are the squared distances.

The squared distance from (x,y) to the line y=k is </span>(y-k)^2
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The squared distance from (x,y) to (p,q) is </span>(x-p)^2+(y-q)^2.<span>
These are equal in a parabola:

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(y-k)^2 =(x-p)^2+(y-q)^2<span>

</span>y^2-2ky + k^2 =(x-p)^2+y^2-2qy + q^2

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Gotta go; more later if I can.

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4.A pipe needs to run from a water main, tangent to a circular fish pond. On a coordinate plane, construct the circular fishpond, the point to represent the location of the water main connection, and all other pieces needed to construct the tangent pipe. Submit your graph. You may do this by hand, using a compass and straight edge, or by using a graphing software program.

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5 0
4 years ago
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Step-by-step explanation:

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3 years ago
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Hope this helps

Have a great day/night

Feel free to ask any questions
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