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snow_lady [41]
3 years ago
14

What is the slope line of m (0,6),(3,0)​

Mathematics
1 answer:
mezya [45]3 years ago
3 0

Answer:

slope= <u>y²-y¹</u>

x²-x¹

<u>0</u><u>-</u><u>6</u>

3-0

<u>-</u><u>6</u>

3

= -2

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if 200 volts comes from 110 turns on a coil, give the number of turns on a coil that yields 154 volts
grigory [225]

Answer:

23.7

Step-by-step explanation:

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3 years ago
Round 6.7086 to the nearest thousandth
Bingel [31]

\text {Hello! Let's solve this Problem!}

\text {To round to the nearest thousandth you must underline the thousandth place}\text {(which is 8), point an arrow to 6 (in the ten-thousandth place)}

\text {If the number is 5 or more you raise the score. Meaning you add 1 to the}\text {thousandth place. If the number is 4 or lower you keep the number the same.}

\text {6 is greater than 5. So this means you add 1 to 8 and it becomes 9. Every}\text {number behind it becomes 0.}

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3 years ago
Using a chart of values, graph the function f(x)=3^x
Citrus2011 [14]
Hey there!

For this problem, I would assume that you must make your own chart of values. You can do this by simply plugging in numbers like 1, 2, 3, etc... Since your graph won't be linear, you might want to do some negative numbers, as well. 

Also because your graph isn't linear, you might want to figure out or determine on your own just how far your curve will go. You can then figure out how many times you need to plug in an additional numbers for your function to then graph. 

I've attached a digital graph of this function, perhaps you can find it useful. 

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8 0
3 years ago
Read 2 more answers
Name a pair of perpendicular lines: <br>is line BC and AJ perpendicular: explain ​
wel
A pair of perpendicular lines would be line CF and line AJ.

Line BC and line AJ are NOT perpendicular because when a pair of lines are perpendicular, all angles become 90 degrees. It is obvious, in the case, if you were to slide line BC on top of line AJ, the angles will not equal 90 degrees.
8 0
3 years ago
A circle with radius 9 has a sector with a central angle of 120°.
Vitek1552 [10]

120º is 1/3 of a complete revolution of 360º. So the area of this sector should be 1/3 the area of the complete circle.

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So the sector has area 81π/3.

Put another way: The area <em>A</em> of a circular sector and its central angle <em>θ</em> (in degrees) occur in the same ratio as the area of the entire circle with radius <em>r</em> according to

<em>A</em> / <em>θ </em>º = (π <em>r </em>^2) / 360º

==>  <em>A</em> = π/360 <em>θ r</em> ^2

In this case, <em>r</em> = 9 and <em>θ</em> = 120º, so

<em>A</em> = π/360 * 120 * 81 = 81π/3

8 0
3 years ago
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