All categories

3 years ago

HELP ME PLEASE ☹️☹️☹️☹️

Mathematics

1 answer:

Zolol [24]3 years ago

6 0

For the 1st one, its 1, and 2

For the 2nd question its -3

You might be interested in

Which value of x is in the solution set of the following inequality. -3x +5 >7

Vadim26 [7]

I’m not sure if this was a typo, but A and B are the same answer. A and B are correct, because when you solve this the answer has to be anything less than -0.6.

8 0

4 years ago

A carton of paper is priced at $27.00 now. If the papergoes on sale for 25% off the current price, what will be the sale price o

Alenkinab [10]

Divide the 27 by 4 and that will give you 6.75. Subract the 6.75 from the 27 and theres your answer (20.25) so the sale price is $20.25

3 0

3 years ago

PLS HELP DUE AT MIDNIGHT

Fudgin [204]

Answer:

Is this a supplementary angle? if yes let me know so that i can help you

4 0

3 years ago

how many terms are in this expression: 4n+2n+9-5 terms are parts between the addition or subtraction sign

Veseljchak [2.6K]

There are 4 terms. Those terms are 4n, 2n, 9, and 5.

5 0

3 years ago

If f ( x ) f(x) is an exponential function where f ( − 3.5 ) = 25 f(−3.5)=25 and f ( 6 ) = 33 f(6)=33, then find the value of f

gavmur [86]

Given:

f(x) is an exponential function.

$f(-3.5)=25, f(6)=33$

To find:

The value of f(6.5).

Solution:

Let the exponential function is

$f(x)=ab^x$ ...(i)

Where, a is the initial value and b is the growth factor.

We have, $f(-3.5)=25$ . So, put x=-3.5 and f(x)=25 in (i).

$25=ab^{-3.5}$ ...(ii)

We have, $f(6)=33$ . So, put x=6 and f(x)=33 in (i).

$33=ab^{6}$ ...(iii)

On dividing (iii) by (ii), we get

$\dfrac{33}{25}=\dfrac{ab^{6}}{ab^{-3.5}}$

$1.32=b^{9.5}$

$(1.32)^{\frac{1}{9.5}}=b$

$1.0296556=b$

$b\approx 1.03$

Putting b=1.03 in (iii), we get

$33=a(1.03)^{6}$

$33=a(1.194)$

$\dfrac{33}{1.194}=a$

$a\approx 27.63$

Putting a=27.63 and b=1.03 in (i), we get

$f(x)=27.63(1.03)^x$

Therefore, the required exponential function is $f(x)=27.63(1.03)^x$ .

4 0

3 years ago