$6\sqrt3\cdot\dfrac{\sqrt3}{3}=\dfrac{(6\sqrt3)(\sqrt3)}{3}\\\\\text{use the associative property}\ (a\times b)\times c=a\times(b\times c)\\\\=\dfrac{(6)(\sqrt3\cdot\sqrt3)}{3}\\\\\text{use}\ \sqrt{a}\cdot\sqrt{a}=a\\\\=\dfrac{(6)(\not3)}{\not3}\qquad\text{cancel 3}\\\\=6$

3 0

3 years ago

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I don't understand the question.

enot [183]

Answer:

The question is asking which combinations of $2x^2-4x+1$ make different types of equations. y=2x^2 makes a quadratic equation, y=-4x+1 makes a linear equation, and y=1 makes a horizontal line

8 0

3 years ago

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If you want to create a pad>let and share it with me, answer this and put the link or code in the comments or your answer.

PIT_PIT [208]

Answer:

Step-by-step explanation:

5 0

3 years ago