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balu736 [363]
3 years ago
7

9th grade Algebra 1 help??

Mathematics
1 answer:
andriy [413]3 years ago
8 0
3 eggs for brownies, 2 eggs for cookies. 

Because the total count went up 2 for one more batch of cookies, you know that 1C(ookies) = 2 eggs
3C = 6 eggs
15 - 6 = 9 eggs
3B(rownies) = 9 eggs
1B = 3 eggs
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Hey, can someone solve this for me? <br><br> 5(x+1)= 4(x-1)+x
Travka [436]
<span>5(x+1)= 4(x-1)+x
5x + 5 = 4x - 4 + x
5x +5 = 5x -4
5 </span>≠<span> -4
x </span>∈ ∅
3 0
3 years ago
What are the sine cosine and tangent of theta=7pi/4 radians
FrozenT [24]

Answer:

see explanation

Step-by-step explanation:

\frac{7\pi }{4} is in the fourth quadrant

Where sin and tan are < 0 , cos > 0

The related acute angle is 2π - \frac{7\pi }{4} = \frac{\pi }{4}

Hence

sin([\frac{7\pi }{4} ) = - sin(\frac{\pi }{4}) = - \frac{1}{\sqrt{2} } = - \frac{\sqrt{2} }{2}

cos(\frac{7\pi }{4}) = cos(\frac{\pi }{4}) =  \frac{\sqrt{2} }{2}

tan(\frac{7\pi }{4}= - tan(\frac{\pi }{4} = - 1

6 0
2 years ago
Read 2 more answers
What is 5/6 times 120 =
Dominik [7]
Answer: you can use take out the 5 and multiply 5 by 120=600.then take out the 6 and multiply 6 by 120=720.then take 600 and 720,put it into a fraction.
6 0
3 years ago
Ricky has a 26-foot ladder. He must have the bottom of the ladder 10 feet from the wall. Will he be able to reach a roof that is
matrenka [14]
Check the picture below.

the ladder is 26ft, the roof is 24ft above, so the ladderis 2ft longer than needed, if you move the ladder 10 feet away, will it give 24 or more?  well, you know already.

6 0
3 years ago
There are 250 wolves in a national park. the wolf population is increasing at a rate of 16% per year. write an exponential model
Helga [31]

\qquad \textit{Amount for Exponential Growth} \\\\ A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ A=250(1 + 0.16)^{t}\implies A=250(1.16)^t \\\\[-0.35em] ~\dotfill

A=P(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\dotfill &1000\\ P=\textit{initial amount}\dotfill &250\\ r=rate\to 16\%\to \frac{16}{100}\dotfill &0.16\\ t=\textit{elapsed time} \end{cases} \\\\\\ 1000=250(1.16)^t\implies \cfrac{1000}{250}=1.16^t\implies 4=1.16^t \\\\\\ \log(4)=\log(1.16^t)\implies \log(4)=t\log(1.16) \\\\\\ \cfrac{\log(4)}{\log(1.16)}=t\implies \stackrel{\textit{about 9 years and 4 months}}{9.34\approx t}

7 0
1 year ago
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