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Rainbow [258]
3 years ago
14

CHECK YOUR KNOWLEDGE

Mathematics
1 answer:
PIT_PIT [208]3 years ago
5 0
1. A rent paid
2. B 10
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Justin is constructing a line through point Q that is perpendicular to line n. He has already constructed the arcs shown. He pla
krek1111 [17]
<span>B. It must be the same as when he constructed the arc centered at point A. This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined. Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing. "... places his compass on point B ..." Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense. A .It must be wider than when he constructed the arc centered at point A. Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer. B It must be the same as when he constructed the arc centered at point A. Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer. C. It must be equal to BQ. Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong. D.It must be equal to AB. Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
8 0
3 years ago
Read 2 more answers
LAST QUSTION OF THE NIGHT!!!!!<br> HELP SHOW WORK PLZ AND THANK YOU!!!
MissTica
Okay, so, to find out if an equation has one solution, an infinite number of solutions, or no solutions, we must first solve the equation:

(a) 6x + 4x - 6 = 24 + 9x

First, combine the like-terms on both sides of the equal sign:

10x - 6 = 24 + 9x

Now, we need to get the numbers with the variable 'x,' on the same side, by subtracting, in this case:

10x - 6 = 24 + 9x
-9x. -9x
______________
X - 6 = 24

Now, we do the opposite of subtraction, and add 6 to both sides:

X - 6 = 24
+6 +6
_________
X = 30

So, this particular equation has one solution.

(a). One solution
_____________________________________________________

(b) 25 - 4x = 15 - 3x + 10 - x

Okay, so again, we combine the like-terms, on the same side of the equal sign:

25 - 4x = 25 - 2x

Now, we get the 2 numbers with the variable 'x,' to the same side of the equal sign:

25 - 4x = 25 - 2x
+ 2x + 2x
________________
25 - 2x = 25

Next, we do the opposite of addition, and, subtract 25 on each side:

25 - 2x = 25
-25 -25
___________
-2x = 0

Finally, because we can't divide 0 by -2, this tells us that this has an infinite number of solutions.

(b) An infinite number of solutions.

__________________________________________________

(c) 4x + 8 = 2x + 7 + 2x - 20

Again, we combine the like-terms, on the same side as the equal sign:

4x + 8 = 4x - 13

Now, we get the 'x' variables on the same side, again, and, we do that by doing the opposite of addition, which, is subtraction:

4x + 8 = 4x - 13
-4x -4x
______________
8 = -13

Finally, because there is no longer an 'x' or variable, we know that this equation has no solution.

(c) No Solution
_________________________________

I hope this helps!
4 0
2 years ago
Bobby catches 8 passes in 3 football games
netineya [11]

Answer:

24 passes in total

Step-by-step explanation:

8*3=24

If you like the answer please put 5 stars

6 0
3 years ago
Ryan earns $5 for each small dog he walks and $8 for each large dog he walks. Today he walked 9 dogs and made a total of $51. Ho
Shalnov [3]
Use a system of equations.

(x=# of small dogs, y=# of big dogs)

x+y=9 (times by -5) -5x-5y=-45
5x+8y=51

Then add the equations together and the x's cancel. 

3y=6
y=2

So he walked 2 big dogs and 7 little dogs.
6 0
3 years ago
-3z-z answer please fast​
ch4aika [34]

Answer:

-4z

Step-by-step explanation:

4 0
3 years ago
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