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attashe74 [19]
3 years ago
14

Can anybody help me im in need of help

Mathematics
2 answers:
soldier1979 [14.2K]3 years ago
8 0
The first question's answer is the second choice. The second question's answer is the first choice. The third question's answer is the second choice.
lilavasa [31]3 years ago
3 0
Part 1: Expand \ 7x(x+4) 

7x*x+7x*4    Distribute 

Use \ Product \ Rule    x^ax^b=x^a^+^b 

7x^2+7x*4
 
 

7x^2+28x

 


Part 2: 4x(2x^3-7x^2+x) 


4x*2x^3+4x*-7x^2+4x*x
 
      Distribute 

4*2xx^3+4x*-7x^2+4x*x 

<span>Use \ Product \ Rule    x^ax^b=x^a^+^b 
</span>
4*2x^1^+^3+4x*-7x^2+4x*x&#10;&#10; &#10; 

&#10;4*2x^4+4x*-7x^2+4x*x&#10; &#10; 

8x^4-4*7xx^2+4x*x   Gather \ like \ terms 

8x^4-4*7x^1^+^2+4x*x 

8x^4-4*7x^3+4x*x 

8x^4-28x^3+4x*x 

8x^4-28x^3+4x^2


Part 3: The \  largest \ number  \ that  \ divides \ evenly  \ into \ 12x \ and  \ 20 \ is  \ 4. 
<span>
</span>GCF = 4<span>


</span><span>Hence Solved 
</span>


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The dimensions of a closed rectangular box are measured as 90 centimeters, 50centimeters, and 90 centimeters, respectively, with
gogolik [260]

Answer:

184 cm²

Step-by-step explanation:

Surface area of the rectangular box is expressed as S = 2(LW+LH+WH)

L is the length of the box = 90 cm

W is the width of the box = 50 cm

H is the height of the box= 90 cm

If there are error of at most 0.2 cm in each measurement, then the total surface area using differential estimate will be expressed as shown;

S = 2{(LdW+WdL) + (LdH+HdL) + (WdH+HdW)

Note that dL = dW = dH = 0.2 cm

Substituting the given values into the formula to estimate the maximum error in calculating the surface area of the box

S = 2{(90(0.2)+50(0.2)) + (90(0.2)+90(0.2)) + (50(0.2)+90(0.2))

S = 2{18+10+18+18+10+18}

S = 2(92)

S = 184 cm²

Hence, the maximum error in calculating the surface area of the box is 184cm²

5 0
3 years ago
PLEASE HELP! (05.01 MC)
Temka [501]

Answer:

3) Option C is correct.

3 over 3 and 61 hundredths = 6 over 7 and 22 hundredths

Step-by-step explanation:

Triangle BDE is dilated by a scale factor of 2 to obtain triangle BAC.

Dilation by a scale factor of 2 means that all the sides of triangle BAC are twice as much as the corresponding sides of triangle BDE.

And triangle BDE is similar to triangle BAC.

It also means that the corresponding angles are necessarily equal.

BD = 2

BE = 3

ED = 3.61

BA = 2 × BD = 2 × 2 = 4

BC = 2 × BE = 2 × 3 = 6

CA = 2 × ED = 2 × 3.61 = 7.22

Cos ∠D according to trigonometric relations is given as (adj/hyp)

Adj = Adjacent side = BE = 3

Hyp = hypotenuse side = ED = 3.61

Cos ∠D = (3/3.61)

Cos ∠A can also be similarly obtained from trigonometric relations as (adj/hyp)

Adj = Adjacent side = BC = 6

Hyp = hypotenuse side = CA = 7.22

Cos ∠A = (6/7.22)

Since the two angles are corresponding angles of two similar triangles,

We can easily see that

Cos ∠D = Cos ∠A

(3/3.61) = (6/7.22) = 0.8310

Which is necessarily equal to each other

Hence, the proportion that proves that Cos ∠D = Cos ∠A is 3 over 3 and 61 hundredths = 6 over 7 and 22 hundredths.

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