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Svetradugi [14.3K]
3 years ago
10

You work in an assembly line. The company determines that the average employ can assemble 4 radios in 90 minutes . For one shift

there are 150 employees and they each work 8 hours. To determine at this rate, how many radios were assembled in the entire plant during the shift you multiply 8 by 60, divide by 90, then multiply by 4. Is this correct?
Mathematics
1 answer:
coldgirl [10]3 years ago
6 0
This is not correct. It is not taking into account the 150 employees.
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Find the equation of the line through (10, 4) that is parallel to the line with the equation
lyudmila [28]

Answer:

x + y = 14

Step-by-step explanation:

Parallel lines have the same slope, so the line's slope will be -1.

Plug this slope and the given point into y = mx + b to find b:

y = mx + b

4 = -1(10) + b

4 = -10 + b

14 = b

Then, plug this and the slope into y = mx + b

y = -x + 14

Then, put this into standard form by moving the x to the other side:

x + y = 14 is the equation in standard form

6 0
3 years ago
WILL MARK BRAINLIEST!!!!PLZ HELP!!!! An expression is shown below: 3pf2 − 21p2f + 6pf − 42p2 Part A: Rewrite the expression by f
Lesechka [4]

Answer:

See below.

Step-by-step explanation:

So, we have:

3pf^2-21p^2f+6pf-42p^2

PART A:

Find the GCF. Notice that we have a 3 in every term and a p in every term. Thus, the GCF is 3p:

3p(f^2-7pf+2f-14p)

This is the most we can do.

PART B:

Continue from where we left off. Factor the entire expression:

3p(f^2-7pf+2f-14p)\\3p(f(f-7p)+2(f-7p))\\3p((f+2)(f-7p))

7 0
3 years ago
1. Four times a number minus twenty-one is the same as six times
Ganezh [65]

Answer: -16

Step-by-step explanation:

Let the number be y

Four times a number minus twenty-one can be written as:

(4 × y) - 21 = 4y - 21

Six times the number plus eleven can be written as:

(6 × y) + 11 = 6y + 11

Combining both equations will give:

4y - 21 = 6y + 11

4y - 6y = 11 + 21

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y = 32/-2

y = -16

The number is -16

7 0
3 years ago
Does anyone know this?
weeeeeb [17]

Answer:

BC = 10.24

Step-by-step explanation:

You can use the Pythagoras theorem for this question

a^{2} + b^{2} = c^{2}

a = 8cm

b = ???

c = 13cm

We will solve for B (length BC)

a^{2} + b^{2} = c^{2}

8^{2} + b^{2} = 13^{2}

Rearrange for b

b^{2} = 13^{2} - 8^{2}

b^{2} = 105

b = \sqrt{105}

b = 10.24

7 0
3 years ago
The diagonals of a square are perpendicular bisectors of each other.<br> True or false ?
kirill [66]

Answer: True

Step-by-step explanation:

This is true because for a square, all angles and sides are equal. That is no side has a longer length than the other. The diagonals of a square are therefore perpendicular bisectors of each other.

I hope this is clear, please mark as brainliest answer

8 0
3 years ago
Read 2 more answers
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