The line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9
<h3>Parallel Equations</h3>
The given equation is:
y = 4x + 5
Compare y = 4x + 5 with the equation y = mx + c
m = 4, c = 5
The equation parallel to y = 4x + 5 will also have a slope, m = 4
The point-slope form of the equation of a line is given as:
y - y₁ = m(x - x₁)
substitute m = 4, x₁ = -2 and y = 1 into the equation above
y - 1 = 4(x - (-2)
y - 1 = 4(x + 2)
y - 1 = 4x + 8
y = 4x + 8 + 1
y = 4x + 9
Therefore the line parallel to y= 4x+ 5 passing through point (-2, 1) is y = 4x + 9
Learn more on equation of a line here: brainly.com/question/13763238
False, -4(X - 5) would be -4x + 20.
Answer: B. 76
Step-by-step explanation: A right triangle is 180 degrees. It has an angle of 90 since it is a right triangle. 90 + 14 = 104. 180 - 104 = 76
First off, let's keep in mind that perpendicular lines have negative reciprocal slopes, hmmm so what's the slope of y = 2x + 5?
well, notice, that equation is in slope-intercept form, thus

.

so, we're really looking for the equation of a line whose slope is -1/2 and runs through 1,4.
We know that
the law of sines established
a/sin A=b/sin B--------sin A=[a*sin B]/b
a=4.5 cm
b=6 cm
B=35°
so
sin A=[4.5*sin 35°]/6-----> sin A=0.43018
A=arc sin(0.43018)-------> A=25.5°
the answer is the option
<span>C) 25.5° </span>