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Ivahew [28]
3 years ago
10

Please help me I will give BRAINLIST and a like :))))

Mathematics
2 answers:
Bingel [31]3 years ago
6 0

Answer:

19%

Step-by-step explanation:

Find the number of female students

3+4+6+3 = 16

P( senior given that it is female = senior/ female

                                                    = 3/16

                                                      =.1875

                                                       18.75%

To the nearest whole percent   19%

Vlada [557]3 years ago
5 0

Answer:

18.75%

Step-by-step explanation:

Hello,

3 students are both female and senior

the total number of students is 7+10+8+5=30

so the probability to select one female senior is 3/30=1/10=0.10

probability to select one female is 16/30=16/30

probability that the student is a senior given that it's female is

=P(female and senior)/P(female)

=1/10*30/16=3/16

hope this helps

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Anna [14]

Answer:

first one x = 26

second one x = 11.12

Step-by-step explanation:

a^2 + b^2 = c^2

24^2 + 10^2 = c^2

676 = c^2

26 = c

a^2 = c^2 - b^2

a^2 = 12^2 - 4.5^2

a^2 = 123.75

a = 11.12

4 0
3 years ago
If x=12 What is the value of the expression2(x)+3
GaryK [48]

Answer:

147

Step-by-step explanation:

2(X)= (X) x (X)

12 x 12 + 3= 144+3=147

7 0
3 years ago
What is the perimeter of a square whose diagonal is 3 square root 2? Show all work on how you got your answer
Alika [10]

Answer:

12

Step-by-step explanation:

Given: Diagonal of square= 3\sqrt{2}

To find the perimeter of square, we need to find the length of sides of square.

∴ Using the formula of diagonal to find side of square.

Formula; Diagonal= s\sqrt{2}

Where, s is side of square.

⇒ 3\sqrt{2} = s\sqrt{2}

Dividing both side by √2

⇒s= \frac{3\sqrt{2} }{\sqrt{2} }

∴s= 3

Hence, Length of side of square is 3.

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Formula; Perimeter= 4s

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∴ Perimeter= 12

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6 0
3 years ago
Determine the equation of the circle graphed below.
sergij07 [2.7K]

Answer:

Equation = (x - 6 )² + ( y + 3 )² = 9

Step-by-step explanation:

The circle passes through ( 6, 0) and  ( 6 , -6)

They are the coordinates of the diameter.

Using this we can find the centre of the circle.

<u>Find the centre of the circle.</u>

Centre of the circle is the mid- point of (6, 0) and ( 6, -6)

      Centre = (\frac{x_1+x_2}{2} , \frac{y_1 + y_2}{2})

                 =(\frac{6 + 6}{2}, \frac{0 + (-6)}{2})\\\\=(6, -3)

<u>Find the radius of the circle.</u>

Radius = \frac{Diameter }{2}

Diameter is the distance between the points (6 , 0) and ( 6, - 6)

Diameter = \sqrt{(x_2 - x_1)^2+ (y_2 - y_1)^2\\}

               =\sqrt{(6-6)^2 + (-6 -0)^2}\\\\=\sqrt{0 + 36} \\\\= 6

Therefore,

    Radius ,r = \frac{6}{2} = 3

<u>Standard equation of a circle:</u>

<u></u>(x - a)^2 + (y - b)^2 = r^2 \ where \ (a , b) \ is \ the\ centre \ coordinates.<u></u>

Therefore , equation of the circle ;

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6 0
3 years ago
Please answer now I’m giving out 100 points
N76 [4]

4 liters of punch can serve 16.

5 liters of punch will be needed for 20 servings.

7 liters of punch will serve 28.

Step-by-step explanation:

Given,

Ratios of liters of punch to servings = 2:8

Let,

x be the servings for 4 liters.

New ratio of liters of punch to servings = 4:x

Using proportion;

Ratio :: New ratio

2:8::4:x

Product of mean = Product of extreme

8*4=2*x\\32=2x\\2x=32

Dividing both sides by 2

\frac{2x}{2}=\frac{32}{2}\\x=16

4 liters of punch can serve 16.

Let,

y be the liters of punch for 20 servings.

New ratio = y:20

Using proportion;

2:8::y:20

Product of mean = Product of extreme

8*y=20*2\\8y=40\\

Dividing both sides by 8

\frac{8y}{8}=\frac{40}{8}

y=5

5 liters of punch will be needed for 20 servings.

Let,

z be the number of servings for 7 liters of punch.

New ratio = 7:z

Using proportion

2:8::7:z\\

Product of mean = Product of extreme

8*7=2*z\\56=2z\\2z=56

Dividing both sides by 2

\frac{2z}{2}=\frac{56}{2}\\z=28

7 liters of punch will serve 28.

Keywords: ratio, proportion

Learn more about ratios at:

  • brainly.com/question/2154850
  • brainly.com/question/2367554

#LearnwithBrainly

4 0
3 years ago
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