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Mariana [72]
3 years ago
12

What is the removal of fish from an area faster than the rate at which they can replace themselves called

Geography
2 answers:
Vesnalui [34]3 years ago
4 0

The answer is overfishing

mario62 [17]3 years ago
3 0
The answer is overfishing because if you remove them faster than they reproduce, the population will get smaller and smaller until there is none.
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Which air masses would have cold, dry air?
NNADVOKAT [17]
Continental Polar and Maritime Polar ; Polar had a direct connotation with the cold. :)
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Which of the following refers to the number and variety of species found on earth?
erik [133]

Answer:

Hey!

Your answer is  Species Diversity!

Explanation:

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Hope this helps!

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4 0
3 years ago
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Find the coordinates of the midpoint of HX
marta [7]

Answer:

M(29, -12)

Explanation:

Given:

H(4\frac{1}{2}, -3\frac{1}{4}), X(2\frac{3}{4}, -2\frac{3}{4})

Required:

Coordinates of the Midpoint of HX

Solution:

Midpoint (M) of HX, for H(4\frac{1}{2}, -3\frac{1}{4}), X(2\frac{3}{4}, -2\frac{3}{4}) is given as

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}).

Let H(4\frac{1}{2}, -3\frac{1}{4}) = (x_1, y_1)

X(2\frac{3}{4}, -2\frac{3}{4}) = (x_2, y_2)

Thus:

M(\frac{4\frac{1}{2} + 2\frac{3}{4}}{2}, \frac{-3\frac{1}{4} + (-2\frac{3}{4})}{2})

Convert to improper fractions

M(\frac{\frac{9}{2} + \frac{11}{4}}{2}, \frac{-\frac{13}{4} + (-\frac{11}{4})}{2})

M(\frac{\frac{18 + 11}{2}}{2}, \frac{\frac{-13 - 11}{4}}{2})

M(\frac{\frac{29}{2}}{2}, \frac{\frac{-24}{4}}{2})

M(\frac{29}{2}*2, \frac{-24}{4}*2

M(29, -12)

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3 years ago
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ryzh [129]
B) is the answere
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2 years ago
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maksim [4K]

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