Question

You are concerned about the rate of death in catfish your aquaculture operation in tanks that have a high amount of algae growth. You collect some of the algae and send it to the university to have it identified. You find that it is a blue-green alga called Anabaena. Anabaena is known to be toxic to fish. You design an experiment to test how much of the algae the fish can stand before they die. You obtain 6 large aquariums (all the same size) and fill them with water taken from a healthy catfish pond at your operation. You put each aquarium on the same bench in the laboratory, where the light and temperature values are identical. You let the water stand for one day before starting the experiment. In aquarium 1, you add 2 grams of algae and no fish. In aquarium 2, you add 20 small catfish and no algae. Aquarium 3 gets 20 catfish and 2 grams of algae, #4 gets 20 catfish and 4 grams of algae, #5 gets 20 catfish and 8 grams of algae, and aquarium #6 gets 20 catfish and 16 grams of algae. The aeration rate of each aquarium is identical. You make two observations at the same time each day for two weeks. You keep track of the numbers of fish in each tank that die.
What is the problem?









What is your hypothesis?













What is the independent variable?

Answer 1

Answer:

Hypothesis is ''With the increase of algae in the aquarium, fish population decreases''.

Explanation:

The main problem was that there is no need for 2 aquarium because there is no need for aquarium 1 which has no fish and aquarium 2 which has fishes but no algae. With the increase of algae in the aquarium, fish population decreases is the hypothesis for this experiment. Concentration of algae is the independent variable of the experiment because there is no effect on it in the experiment.