What is the equation of the line that passes through the point (-2,2) and (0,5)? A. Y=-3/2x+5 B.Y=x-5 C.Y=3/2x+5 D. Y=x+5

Mathematics

1 answer:

Bond [772]3 years ago

6 0

Bbbbbbbbbbbbbbbbbbbbbbbb

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Keith_Richards [23]

Answer: 1.8032 x 10^13

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vichka [17]

Answer:

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Step-by-step explanation:

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Find the slope of the line graphed below.

Finger [1]

to get the equation of any straight line, we simply need two points off of it, let's use the ones provided in the picture below.

$(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{3}~,~\stackrel{y_2}{-3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-3}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{1}}} \implies \cfrac{-7}{2}$

$\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{-\cfrac{7}{2}}(x-\stackrel{x_1}{1}) \\\\\\ y-4=-\cfrac{7}{2}x+\cfrac{7}{2}\implies y=-\cfrac{7}{2}x+\cfrac{7}{2}+4\implies y=-\cfrac{7}{2}x+\cfrac{15}{2}$