The correct option about squaring the binomial is that B. The student is wrong. There is a missing term.
<h3>How to use binomial theorem?</h3>
We want to square a binomial and using pascal's triangle in binomial theorem, we know that; (x + a)² will follow the pattern;
1x²a⁰ + 2a¹x¹ + 1x⁰a²
Thus, we can say that the expression (x + 3)² will give us;
x² + 2(3x) + 9a²
= x² + 6x + a²
Thus, we can say that the correct option about squaring the binomial is that B. The student is wrong. There is a missing term.
Complete Question is;
A student is instructed to square a binomial, and gets the result shown. Choose the correct description of the student's work. (x + 3)² = x² + 9 Choose the correct answer below.
A. The student is wrong. You cannot square a binomial, only monomials.
B. The student is wrong. There is a missing term.
C. The student is correct. Each given term is squared.
D. The student is wrong. The student should add the threes instead of multiplying them.
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Answer:
A)
y^2-6y = 0
or, y(y-6) = 0
or, y = 0 or y = 6
B)
n^2+5n+7 = 7
or, n^2+5n+7-7 = 7-7 ( Subtracting 7 from both sides)
or, n^2+5n = 0
or, n(n+5) = 0
or, n=0 or n= -5
C)
2t^2-14t+3 = 3
or, 2t^2-14t = 0
or, 2t(t-7) = 0
or, t=0 or t=7
D)
1/3x^2+3x-4 = -4
or, 1/3x^2+3x = 0
or, 1/3x(x+9) = 0
or, x=0 or x= -9
E)
Zero is a common solution to each of the equations. This is because each of the equations had a variable outside the parenthesis with an operation of multiplication.
THANK YOU FOR READING.
The equation of the line with a positive slope is y≤5x-1. This eliminates choice C (third choice). From there, we can start to put the equations into slope-intercept form.
y≥3x+4
y≥-3x+4
y≥-3x-4
We see that the the equation for the second line (on the graph, not above) is y≥-3x+4. The answer is Choice 2 because both lines match its equations.
y≤5x-1 and 3x+y≥4
:)