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scZoUnD [109]
3 years ago
5

The length Oné side of square city block si 462 meters what is the perimeter of the block in meters

Mathematics
1 answer:
just olya [345]3 years ago
4 0

Step-by-step explanation:

hi baby how are u I had a few questions from you, can you answer?

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How to solve <img src="https://tex.z-dn.net/?f=log_%7By%7D%285y%29%20%3D%202" id="TexFormula1" title="log_{y}(5y) = 2" alt="log_
Natalija [7]

Answer:

  y = 5

Step-by-step explanation:

Expand the logarithm:

\log_y{(5)}+\log_y{(y)}=2\\\\\dfrac{\log{(5)}}{\log{(y)}}+1=2 \quad\text{change of base formula}\\\\\dfrac{\log{(5)}}{\log{(y)}}=1 \quad\text{subtract 1}\\\\\log{(5)}=\log{(y)} \quad\text{multiply by log(y)}\\\\5=y \quad\text{take the anti-log}

_____

You can also take the antilog first:

  5y = y²

  y(y -5) = 0 . . . . . subtract 5y, factor

  y = 0 or 5 . . . . . y=0 is not a viable solution, so y=5.

5 0
4 years ago
Write an equation to represent this situation and answer the question
il63 [147K]
The equation would be x+3x(10+2x)=142
The sides are 22cm , 54cm and 66 cm.
7 0
3 years ago
How do I work out this problem?
cluponka [151]
First we need to find ∡PRQ. To do this we can use the fact that the sum of the interior angles of a triangle is 180°:

180=R+P+Q
180=R+40+105
180=R+145
R=180-145
R=35

Now, we can use the fact that a strait line (like SRQ) is also 180°:
SRQ=180-R
SRQ=180-35
SRQ=145 °
4 0
4 years ago
Help Answer this question to be the brainliest
mote1985 [20]

Answer:

B

Step-by-step explanation:

As it rotate around m it's going to form a half sphere

4 0
3 years ago
Figure RHOM is a rhombus. and are the diagonals of the rhombus, as well as angle bisectors of the vertex angles, and they create
Ganezh [65]

Answer:

∠MSR is right angle


Step-by-step explanation:

It is given that RHOM is a Rhombus

Also ΔHOM, ΔMHR, ΔRHO and ΔOMR are isosceles triangles

Let us take ΔMSR and ΔRSH

∠MRS =∠HRS            ( since it is given that the diagonal RO bisects ∠R)

∠RMS =∠RHS     ( since Δ MRH is isosceles triangle )

RS = RS        ( common side )

By AAS congruency rule ΔMSR ≅ ΔHSR

so we have

∠MSR=∠RSH  ( corresponding parts of congruent triangles are congruent)

also we have

∠MSR +∠RSH =180°   ( supplementary angles)

∠MSR +∠MSR=180°          ( since ∠MSR=∠RSH)

2∠MSR= 180°

∠MSR =90°

Hence ∠MSR is right angle


6 0
3 years ago
Read 2 more answers
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