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NikAS [45]
3 years ago
14

What is the measure of angle aec?

Mathematics
2 answers:
garik1379 [7]3 years ago
7 0
Well what does it look like? I'll be glad to help but it would be easier with a picture.
harina [27]3 years ago
4 0
Yes you better show the picture
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URGENT!!!!!!
Zinaida [17]

Answer: Choice B

a_n = 10(1/2)^(n-2) is the nth term

average rate of change = -35/3

=======================================================

Explanation:

Each time x increases by 1, y is cut in half. For instance, going from (2,10) to (3,5) shows this.

If we want to go in reverse, decreasing x by 1 will double the y value. So (1,20) is another point and (0,40) is another. We'll be using (0,40) and (3,5) because we want the average rate of change from x = 0 to x = 3. I'm using x in place of n here.

Use the slope formula to find the slope of the line through (0,40) and (3,5)

m = (y2-y1)/(x2-x1)

m = (5-40)/(3-0)

m = -35/3

The negative slope means the line goes downhill as you read it from left to right. The average rate of change from n = 0 to n = 3 is -35/3

The nth term of this geometric sequence is 20(1/2)^(n-1) since 20 is the first term (corresponds to n = 1) and 1/2 is the common ratio. Your teacher has done a bit of algebraic manipulation to change the n-1 into n-2. This means the 20 has to change to 10 to counterbalance.

In other words, 20(1/2)^(n-1)  is equivalent to 10(1/2)^(n-2) when n starts at n = 1.

6 0
3 years ago
For what values of b are the vectors [−18, b, 9] and [b, b2, b] orthogonal? (Enter your answers as a comma-separated list. If an
bearhunter [10]

Answer:

Therefore the given vectors are orthogonal for b = 0,±3.

Step-by-step explanation:

If  \vec a and  \vec b are two vectors orthogonal, then the dot product of \vec a and \vec b will be zero.

i.e \vec a. \vec b =0

If  \vec a = x_1\hat i+y_1\hat j +z_1\hat k  and \vec b = x_2\hat i+y_2\hat j +z_2\hat k

\vec a. \vec b=( x_1\hat i+y_1\hat j +z_1\hat k).( x_2\hat i+y_2\hat j +z_2\hat k)

     =x_1 x_2+y_1y_2+z_1z_2

Given two vectors are (-18,b,9) and (b,b²,b)

Let

\vec P= -18 \hat i+b\hat j +9 \hat k

and

\vec Q = b \hat i+b^2 \hat j +b\hat k

Therefore,

\vec P.\vec Q

=( -18 \hat i+b\hat j +9 \hat k).( b \hat i+b^2 \hat j +b\hat k)

=(-18).b+b.b²+9.b

= -18b+b³+9b

= b³-9b

Since \vec P and \vec Q are orthogonal. Then \vec P.\vec Q = 0.

Therefore,

b³-9b= 0

⇒b(b²-9)=0

⇒b =0 or b²=9

⇒b=0 or b =±3

Therefore the given vectors are orthogonal for b = 0,±3.

8 0
3 years ago
Juan quiere saber el área de sus dos terrenos realiza las operaciones correspondientes 7 enteros un cuarto 9.50 m dos enteros 3/
AURORKA [14]

Answer:

your answer will be 24.2

Step-by-step explanation:

5 0
3 years ago
Geri jogs every fourth day. Sarah jogs along the same path every fifth day. Both girls jog on the path on July 7. What is the ne
irga5000 [103]

Answer:

July 27

Explanation:

7 x 4 = 27

6 0
3 years ago
Read 2 more answers
Please help me with this question I’m giving brainliest.
alexira [117]

Answer:

b should be the answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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