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bija089 [108]
3 years ago
14

Which of the linear equations expresses the situation? Alliance Cannery received an order for 384 cans of food. The order can be

made up of a combination of cans of fruit, which are processed at a rate of 24 cans per minute, and cans of vegetables, which are processed at a rate of 64 cans per minute.
x = number of minutes for fruit cans
y = number of minutes for vegetable cans
Mathematics
2 answers:
romanna [79]3 years ago
9 0

The second option, 24x + 64y = 384

kirill [66]3 years ago
3 0

Answer:

24x+64y=384

Step-by-step explanation:

Let x = number of minutes for fruit cans

Let y = number of minutes for vegetable cans

Cans of fruit, which are processed at a rate of 24 cans per minute, making them 24x

Cans of vegetables, which are processed at a rate of 64 cans per minute, making them 64y

Alliance Cannery received an order for 384 cans of food, so the equation is written as:

24x+64y=384

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Landon played football last week he played 22 minutes on Monday 19 minutes on Tuesday and 33 minutes on Wednesday on Thursday he
ladessa [460]

Answer:

32

Step-by-step explanation:

M: 22

T:19

W:33

Th: 2m, if m=22, Th=44

22+19+33+44=118

150-118=32

So he played for 32 minutes on Friday

4 0
3 years ago
BRAINLIEST IF CORRECT
Softa [21]

Answer:

what's the question?????????

7 0
3 years ago
Read 2 more answers
HELP PLEASE!!! I need help with 94 if you could show the steps that would be very helpful!
aksik [14]
A combination is an unordered arrangement of r distinct objects in a set of n objects. To find the number of permutations, we use the following equation:

n!/((n-r)!r!)

In this case, there could be 0, 1, 2, 3, 4, or all 5 cards discarded. There is only one possible combination each for 0 or 5 cards being discarded (either none of them or all of them). We will be the above equation to find the number of combination s for 1, 2, 3, and 4 discarded cards.

5!/((5-1)!1!) = 5!/(4!*1!) = (5*4*3*2*1)/(4*3*2*1*1) = 5

5!/((5-2)!2!) = 5!/(3!2!) = (5*4*3*2*1)/(3*2*1*2*1) = 10

5!/((5-3)!3!) = 5!/(2!3!) = (5*4*3*2*1)/(2*1*3*2*1) = 10

5!/((5-4)!4!) = 5!/(1!4!) = (5*4*3*2*1)/(1*4*3*2*1) = 5

Notice that discarding 1 or discarding 4 have the same number of combinations, as do discarding 2 or 3. This is being they are inverses of each other. That is, if we discard 2 cards there will be 3 left, or if we discard 3 there will be 2 left.

Now we add together the combinations

1 + 5 + 10 + 10 + 5 + 1 = 32 choices combinations to discard.

The answer is 32.

-------------------------------

Note: There is also an equation for permutations which is:

n!/(n-r)!

Notice it is very similar to combinations. The only difference is that a permutation is an ORDERED arrangement while a combination is UNORDERED.

We used combinations rather than permutations because the order of the cards does not matter in this case. For example, we could discard the ace of spades followed by the jack of diamonds, or we could discard the jack or diamonds followed by the ace of spades. These two instances are the same combination of cards but a different permutation. We do not care about the order.

I hope this helps! If you have any questions, let me know :)








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3 years ago
Alexia's bathroom has a tub in the shape of a rectangular prism with a length of 1.5 meters, a width of 0.5 meter, and a height
disa [49]
The answer would be 0.3m^3 . Good luck! :)
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Nachelle goes out to lunch. The bill, before tax and tip, was $8.10. A sales tax of 4% was added on. Nachelle tipped 17% on the
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Step-by-step explanation:

Nachelle goes out to lunch. The bill, before tax and tip, was $8.10. A sales tax of 4% was added on. Nachelle tipped 17% on the amount after the sales tax was added. How much was the sales tax? Round to the nearest cent.

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