Answer:
14x + 2
Step-by-step explanation:
Perimeter = sum of the measures of each side
If a triangle has side lengths of 3x+ 2, 6x, and 5x then the perimeter of that triangle is equal to 3x + 2 + 6x + 5x
Notice that the expression 3x + 2 + 6x + 5x has similar terms so to get the simplist version of the perimeter we would simply combine like terms
3x + 6x + 5x = 14x
The perimeter would = 14x + 2
Log 2 over 3 = 0.10034333188
Answer:
The answer is
<h2>660.5 square feet</h2>
Step-by-step explanation:
Area of a circle = πr²
where r is the radius
From the question
diameter = 29 feet
To find the radius given the diameter we use the formula
So the area of the circle is
We have the final answer as
<h3>660.5 square feet</h3>
Hope this helps you
Answer:
The integrals was calculated.
Step-by-step explanation:
We calculate integrals, and we get:
1) ∫ x^4 ln(x) dx=\frac{x^5 · ln(x)}{5} - \frac{x^5}{25}
2) ∫ arcsin(y) dy= y arcsin(y)+\sqrt{1-y²}
3) ∫ e^{-θ} cos(3θ) dθ = \frac{e^{-θ} ( 3sin(3θ)-cos(3θ) )}{10}
4) \int\limits^1_0 {x^3 · \sqrt{4+x^2} } \, dx = \frac{x²(x²+4)^{3/2}}{5} - \frac{8(x²+4)^{3/2}}{15} = \frac{64}{15} - \frac{5^{3/2}}{3}
5) \int\limits^{π/8}_0 {cos^4 (2x) } \, dx =\frac{sin(8x} + 8sin(4x)+24x}{6}=
=\frac{3π+8}{64}
6) ∫ sin^3 (x) dx = \frac{cos^3 (x)}{3} - cos x
7) ∫ sec^4 (x) tan^3 (x) dx = \frac{tan^6(x)}{6} + \frac{tan^4(x)}{4}
8) ∫ tan^5 (x) sec(x) dx = \frac{sec^5 (x)}{5} -\frac{2sec^3 (x)}{3}+ sec x
