The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
A segment is a region bounded by a chord of a circle and the intercepted arc of the circle. A segment with an intercepted arc less than a semicircle is called a minor segment.
Step-by-step explanation:
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101 2/3
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The trinomial that results from foiling the binomials is 6x^2+41x+30.
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The Answer is 18
Step-by-step explanation:
2 1/4 X 8= 18