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Paladinen [302]
3 years ago
10

find the difference between the simple interest and compound interest on 2500 for 2 years at 4% per annum , compound interest be

ing reckoned semi annually
Mathematics
1 answer:
EastWind [94]3 years ago
6 0

Answer:

Results are below.

Step-by-step explanation:

Giving the following information:

Principal (P)= $2,500

Interest rate= 4%

Number of periods= 2 years

<u>First, we will determine the interest earned using the simple interest formula:</u>

I= P*r*t

I= 2,500*0.04*2

I=$200

<u>Now, using the compound interest formula:</u>

I= [P*(1 + r)^t] - P

r= 0.04/2= 0.02 (semi annual interest rate)

t=2*2= 4 semesters

I= [2,500*(1.02^4)] - 2,500

I= $206.08

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Suppose that it is known that the number of items produced in a factory during a week is a random variable with mean 50. If the
iVinArrow [24]

Answer:

The probability would be 0.9586

Step-by-step explanation:

Given,

Mean, \mu = 50,

Variance, \sigma^2 = 24

Standard deviation,

\sigma = \sqrt{24}=2\sqrt{6},

If X represents the number of items produced in a factory during a week.

Hence, the probability that this weeks production will be between 40 and 60

=P(40 < X < 60)

=P(\frac{40-\mu}{\sigma} < \frac{X-\mu}{\sigma} < \frac{60-\mu}{\sigma})

=P(\frac{40-50}{2\sqrt{6}} < z < \frac{60-50}{2\sqrt{6}})

=P(-\frac{10}{2\sqrt{6}} < z < \frac{10}{2\sqrt{6}})

=P(-2.041 < z < 2.041)

=P(z< 2.041) - P(z< -2.041)

Using z score table

= 0.9793 - 0.0207

= 0.9586

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Which of the graphs below would result if you made the leading term of the
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Find the inverse matrix or type "none". (use decimals) {11 -5 3 -1}
alexira [117]

The inverse of the matrix  \left[\begin{array}{cc}11&-5\\3&-1\end{array}\right] is the matrix \left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right] .

The inverse of a matrix A is calculated by the formula:

A' = (1/|A|)(Adj A),

where A' represents the inverse of matrix A,

|A| represents the determinant value of matrix A, and

Adj A represents the Adjoin matrix of matrix A.

So, to calculate the inverse of the matrix  \left[\begin{array}{cc}11&-5\\3&-1\end{array}\right] , we will first calculate its Adj.

Adj = \left[\begin{array}{cc}-1&-3\\5&11\end{array}\right] ^{T}= \left[\begin{array}{cc}-1&5\\-3&11\end{array}\right].

Now, we calculate |A| = 11*(-1) - (-5)*3 = -11 + 15 = 4.

Therefore A' = (1/|A|)(Adj A),

or, A' = (1/4)*\left[\begin{array}{cc}-1&5\\-3&11\end{array}\right] ,

or, A' = \left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right] .

Therefore, the inverse of the matrix  \left[\begin{array}{cc}11&-5\\3&-1\end{array}\right] is the matrix \left[\begin{array}{cc}\frac{-1}{4} &\frac{5}{4} \\\\\frac{-3}{4} &\frac{11}{4} \end{array}\right] .

Learn more about the inverse of a matrix at

brainly.com/question/16862241

#SPJ10

4 0
2 years ago
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