Answer: A'(-10, -4) and C''(-6, -8) B. A'(-10, -4) and C"(-18, -24) C. A'(-30, -12) and C"(-18, -24) D. A'(-30, -12) and C"(-4, -6) E. A'(-10, -4) and C"(-4, -6)
Answer:
.25
Step-by-step explanation:
The question is an illustration of combination and there are 729 potential pass codes available
<h3>How to determine the number of potential pass codes?</h3>
The given parameters are
Symbols available = 9
Length of pass code = 3
From the question, we understand that a symbol may be entered any number of times.
This means that each of the 9 available symbols can be used three times
So, the number of potential pass codes is
Passcodes = 9 * 9 * 9
Evaluate the product
Passcodes = 729
Hence, there are 729 potential pass codes available
Read more about combination at:
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