Speed = slope of the line = 20 / 0.5 = 40 km / hr
Second part will be a line with downward slope from the end of the horizontal line Slop = 20 / 1/3 (=60 km/h) So it will pass through the 65 on horizontal axis.
She would have $7160.86 left over in cash here's why.....
she starts off with $8,322.65 and spends $830.98 on rent $8,322.65-$830.98= $7,491.67
then spends $210.36 on food and another $120.45 on gas
$7,491.67-$210.36= $7,281.31 - $120.45= $7,160.86 <---- Left over $
As the question say this problem is a practice of the law of cosines!
The law of cosine: c^2=a^2+b^2-2ab*cos*c for any side a, b and c
The law can also be written as c=sqrt(a^2+b^2-2abcosc)
Now use this formula!(note cos 100 degrees is about 0.8623)
c=sqrt(15^2+16^2-2*15*16*cos100)
solving this we can MN is about 23.75
Round this to the nearest tenths now!
We get 23.8!
Thus the answer is D
