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3 years ago

Help me with number question 7

Mathematics

1 answer:

oksano4ka [1.4K]3 years ago

5 0

Just use the Pythagorean Theorem
(9 +x)^2 = 15^2 + x^2
x^2 + 18x + 81 = 225 + x^2
18x = 144
x = 8
So the three sides of the triangle are
15, 8 and 17

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There are 21 bags of pears on a market stall.

geniusboy [140]

Answer:

13 pears in the 21st bag

Step-by-step explanation:

mean = total number of pears/total number of bags

8 = x/21

x = 168

number of pears in 20 bags = (6 x 2) + (7 x 6) + (8 x 9) + (9 x 1) + (10 x 2)

= 155

number of pears in the 21st bag = 168 - 155

= 13

4 0

3 years ago

What is The value of -8/14 · 20/64

Genrish500 [490]

The answer is -5/28

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3 years ago

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Solve 4/9x+7=1/2.<br><br> Solve 1/8x−12=3/4.

Elenna [48]

$\# 1 \\\\ \frac{4}{9}x+7=\frac{1}{2} \\\\ \frac{4x}{9}=\frac{1}{2}-7^{(2} \\\\ \frac{4x}{9}=\frac{1-14}{2} \\\\ \frac{4x}{9}=-\frac{13}{2} \\\\ 4x=-\frac{9*13}{2} \\\\ x=-\frac{\frac{9*13}{2}}{4} \\\\ x=-\frac{117}{2}*\frac{1}{4} \\\\ \boxed{x=-\frac{117}{8}=-14\frac{5}{8}}$

$\#2 \\\\ \frac{1}{8}x-12=\frac{3}{4} \\\\ \frac{1}{8}x=\frac{3}{4}+12^{(4} \\\\ \frac{x}{8}=\frac{3+48}{4} \\\\ \frac{x}{8}=\frac{51}{4} \\\\ x=\frac{\not8*51}{\not4} \\\\ x=2*51 \\\\ \boxed{x=102}$

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3 years ago

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nickel has an approximate diameter of 20 mm and an approximate thickness of 2 mm what is the approximate volume of a stack of 40

ziro4ka [17]

Answer:

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

Step-by-step explanation:

A nickel can be modelled by the formula of a right cylinder, the approximate volume of the stack of nickels ( $V_{net}$ ), measured in cubic milimeters, is the product of the number of elements ( $n$ ), no unit, and the volume of each element ( $V$ ), measured in cubic milimeters. That is:

$V_{net} = n\cdot V$ (1)

By volume equation of right cylinder, we have the following formula:

$V_{net} = \frac{\pi}{4}\cdot n \cdot D^{2}\cdot h$ (2)

Where:

$n$ - Amount of nickels, no unit.

$D$ - Diameter of nickel, measured in milimeters.

$h$ - Thickness of nickel, measured in milimeters.

If we know that $n = 40$ , $D = 20\,mm$ and $h = 2\,mm$ , then the net volume of the stack of nickels is:

$V_{net} = \frac{\pi}{4}\cdot (40)\cdot (20\,mm)^{2}\cdot (2\,mm)$

$V_{net} \approx 25132.741\,mm^{3}$

The approximate volume of a stack of 40 nickels is 25132.741 cubic milimeters.

8 0

3 years ago

Clara wants to cover the top of her jewelry box. The top of the box is a rectangle with a length of 9.4 cm and a width of 8.3 cm

Pavlova-9 [17]

Answer: 78.02 cm²

Step-by-step explanation:

1. To solve this problem you need to apply the formula for calculate the area of a rectangle, which is shown below:

$A=l*w$

Where $A$ is the area of the rectangle, $l$ is its lenght and $w$ is its width.

2. You know that the rectangle has a length of 9.4 cm and a width of 8.3 cm, therefore, you must substitute these values into the formula. Then, you obtain the following result:

$A=(9.4cm)(8.3cm)\\A=78.02cm^{2}$

5 0

3 years ago