I’ve answered this question before, so please see the
attached image.
The solution would be like this for this specific problem:
1, 4, 5, 8 = 55<span>
2, 3 , 6, 7 = 125
9, 12, 13, 16 = 80
10, 11, 14 ,15 = 100</span>
<span>So, the angle measures that are correct are:
</span>
m12 = 100
m8 = 55
m14 = 100
<span>m16 = 80</span>
Answer:
7^12=13,841,287,201
Step-by-step explanation:
when you are putting a power to a power, you just multiply the powers by each other
Answer:
10.67
Step-by-step explanation:
The 10 stays as it is. The 2/3 is approximated by 0.67 (to the nearest hundredth). Thus, we have 10.67 to the nearest hundredth.


so the ODE is indeed exact and there is a solution of the form
. We have




With
, we have

so
