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timama [110]
3 years ago
9

7200 divided by Y = 90 tutorial

Mathematics
1 answer:
lukranit [14]3 years ago
7 0
Y= 80. If you divide 7200 by 90 you will get 80
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Please please help please
valentina_108 [34]

Answer:

Greater Than [The second choice]

Step-by-step explanation:

8 0
3 years ago
B. How long does it take the car to travel 26 miles at this speed?
VikaD [51]

Answer:

Step-by-step explanation: about 6-5hours

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3 years ago
Two basketball players average the same number of points per game.What information would be most helpful in determining which pl
mr_godi [17]

Answer:

Solution:

To Measure Variability we use four Measures

1. Range

2. Inter-Quartile Range

3. Variance

4. Standard Deviation

Averages are same , it means Mean of the two set of Data are same.

→the average number of points each player’s team scores per game can also determine variability.

→the total number of points each player has scored can also measure variability.

→As range is Minimum Value subtracted from Maximum Value of the given set of Data. So, it can be the measure to determine  variability.

So, Option B: →the number of games each player has played can't Determine a player’s game performance showing the least variability among all the options provided.

And if you want to determine variability, which helps us in determine which player's performance is better then it would be option A which is the most and least points each player has scored in a game.

8 0
3 years ago
WHAT NUMBER SHOULD REPLACE THE QUESTION MARK?<br> ANSWER ONLY IN DIGITS
deff fn [24]

Answer:

38 or 36 if there's options

Step-by-step explanation:

6 0
3 years ago
PLZ HELP IM 100% LOST ON THIS
xenn [34]

The equation f(x)=g(x) is

|x-4|-11=-\sqrt{5x}

Some observations:

  • \sqrt{5x} is defined only as long as 5x\ge0, or x\ge0
  • wherever \sqrt{5x} is defined, its value must be non-negative, so that -\sqrt{5x} is never positive
  • by the definition of absolute value, we have |x-4|=x-4 if x\ge4, and |x-4|=-(x-4)=4-x if x. Then

|x-4|-11=\begin{cases}x-15&\text{for }x\ge4\\-x-7&\text{for }x

If x, the equation becomes

-x-7=-\sqrt{5x}\implies x+7=\sqrt{5x}

Taking the square of both sides gives

(x+7)^2=\left(\sqrt{5x}\right)^2\implies x^2+14x+49=5x\implies x^2+9x+49=0

but since the discriminant is 9^2-4\cdot1\cdot49, there are no real solutions.

If x\ge4, then

x-15=-\sqrt{5x}

Taking squares gives

(x-15)^2=\left(-\sqrt{5x}\right)^2\implies x^2-30x+225=5x

and solving by the quadratic formula gives two potential solutions,

x=\dfrac{35\pm5\sqrt{13}}2

which have approximate values of 8.49 and 26.51.

We know for any value of x that g(x)\le0. We have f(8.49)\approx-6.51 and f(26.51)\approx11.51, so only the first solution 8.49 is valid.

8 0
4 years ago
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