Thinking about the graph of y, the rate of change is zero whenever there is an extremum.
First, differentiate y.
Next, find the zeros of y' by factoring.
Now, we substitute these x-values into the
original equation to find the coordinates.
Answer:
Help you with what? their is nothing!
Answer with explanation:
For, a Matrix A , having eigenvector 'v' has eigenvalue =2
The order of matrix is not given.
It has one eigenvalue it means it is of order , 1×1.
→A=[a]
Determinant [a-k I]=0, where k is eigenvalue of the given matrix.
It is given that,
k=2
For, k=2, the matrix [a-2 I] will become singular,that is
→ Determinant |a-2 I|=0
→I=[1]
→a=2
Let , v be the corresponding eigenvector of the given eigenvalue.
→[a-I] v=0
→[2-1] v=[0]
→[v]=[0]
→v=0
Now, corresponding eigenvector(v), when eigenvalue is 2 =0
We have to find solution of the system
→Ax=v
→[2] x=0
→[2 x] =[0]
→x=0, is one solution of the system.
Answer:
E(Y) = $0.5
Var(Y) = 14.25
you should pay the same amount $0.5
Step-by-step explanation:
E(Y) = = Σ(YP)
P = probability of each outcomes.
Var(Y) = Σ
p − (μ x μ)
E(Y) = (2 x 0.25) +(6 x 0.25) + (0.5 x (-3)) = $0.5
Var(Y) = (
x 0.25) + (
x 0.25) +(
x 0.5) - (
)
= 14.5 - 0.25
Var(Y) = 14.25
for the difference between the payoff and cost of playing to have mean 0, you should pay the same amount $0.5
