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andrew-mc [135]
3 years ago
11

HELP!!! WILL GIVE BRAINLIEST!!!! 40 POINTS!!!!!! The agriculture department of a university works with individuals wanting to bu

ild greenhouses heated with only plastic. The department raised funding for 3,450 greenhouses. The program started with a group of 310 existing greenhouses. The number grew to 3,262 greenhouses 10 years after inception. Which equation can be used to model the relationship between the number of greenhouses outfitted depending on the number of years since the project began?
Mathematics
1 answer:
alexgriva [62]3 years ago
6 0

Answer:

Should be something along the lines of:

3,450 = 326x - 310

Step-by-step explanation:

First, let's start with the number of years. Assume the number of years is x. 3262 greenhouses amounts to about 326 greehouses/year. The other number was the existing greenhouses, but we want just how many greenhouses that were built, per the subtraction sign.

Hope this helps!! : )

Sorry if I am wrong, haven't done equations in a while.

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inn [45]
False that is false hope this helps you
3 0
3 years ago
Suppose you pay back $575 on a $525 loan you had for 75 days. What was your simple annual interest rate? State your result to th
KengaRu [80]

The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.

<h3>What is the interest rate behind a pay back?</h3>

In this situation we assume that the loan does not accumulate interests continuously in time. Hence, the <em>interest</em> rate for paying the loan back 75 days later is:

575 = 525 · (1 + r/100)

50 = 525 · r /100

5000 = 525 · r

r = 9.524

The loan has an <em>interest</em> rate of 9.524 % for 75 days. <em>Simple annual interest</em> rate is determine by rule of three:

r' = 9.524 × 365/75

r' = 46.350

The <em>simple annual interest</em> rate for the $ 525 loan is equal to 46.35 %.

To learn more on interests: brainly.com/question/26457073

#SPJ1

7 0
2 years ago
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
Draw a circle at the coordinates listed
lawyer [7]
There are no coordinates listed, Sorry.
3 0
3 years ago
Domain: -00 &lt; x &lt; 00<br><br>Range: pi/2 ≤ y ≤ pi/2<br><br> what is tan^ -1 (1) =​
e-lub [12.9K]

Answer:

π/4

Q1

Step-by-step explanation:

Other options for arctan(1) is 5π/4 + nπ, where n is a whole number, but they are all outside the Range.

6 0
3 years ago
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