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2 years ago

Need a simple Math question Answered

Mathematics

2 answers:

Molodets [167]2 years ago

7 0

Answer:

7.4

Step-by-step explanation:

Phoenix [80]2 years ago

4 0

Convert 7 to a fraction with 5 on the bottom
35/5+2/5= 37/5 or 7.4

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I need help solving these problems

Delicious77 [7]

QUESTION 1

$4 {p}^{2} = 2 \times 2\times {p} \times p$

QUESTION 2

$39 {b}^{3} {c}^{2} = 3 \times 13 \times {b} \times b \times b\times {c} \times c$

QUESTION 3

$100 {x}^{3} y {z}^{2} = {2} \times 2 \times {5} \times 5 \times {x} \times x \times x\times y \times {z} \times z$

QUESTION 4

$66 {d}^{4} = 2 \times 3 \times 11 \times {d} \times d \times d \times d$

QUESTION 5

$85 {x}^{2} {y}^{2} = 5 \times 17 \times {x} \times x \times {y} \times y$

QUESTION 6

$18xy = 2 \times {3}^{2} \times x \times y$

$36 {y}^{2} = {2}^{2} \times {3}^{2} \times {y}^{2}$

The greatest common factor is the product of the least powers of the common factors;

$GCF=2 \times {3}^{2} \times y$

$GCF=18y$

QUESTION 7

$25mn = {5}^{2} \times m \times n$

$21m = 3 \times 7 \times m$

$GCF=m$

QUESTION 8

$15a = 3 \times 5 \times a$

$28a {b}^{2} = {2}^{2} \times 7 \times a \times {b}^{2}$

$GCF=a$

QUESTION 9

$24 {d}^{2} = {2}^{3} \times 3 \times {d}^{2}$

$30 {c}^{2} d = 2 \times 3 \times 5 \times d$

$GCF=2 \times 3 \times d$

$GCF=6d$

QUESTION 10

$20gh = {2}^{2} \times 5 \times g \times h$

$36 {g}^{2} {h}^{2} = {2}^{2} \times {3}^{2} \times {g}^{2} \times {h}^{2}$

$GCF= {2}^{2} \times g \times h$

$GCF=4gh$

QUESTION 11

$17 {c}^{3} {d}^{2} = 17 \times {c}^{3} \times {d}^{2}$

$5 {c}^{2} {d}^{2} = 5 \times {c}^{2} \times {d}^{2}$

$GCF= {c}^{2} \times {d}^{2}$

$GCF= {c}^{2}{d}^{2}$

4 0

2 years ago

How to find the area and perimeter of a parrallogram?

Y_Kistochka [10]

Answer:

Opposite sides are equal in length and opposite angles are equal in measure. To find the area of a parallelogram, multiply the base by the height. The formula is: A = B * H where B is the base, H is the height, and * means multiply.

Step-by-step explanation:

7 0

2 years ago

The maximum flow of water in a pipe is modeled by the formula Q=Av, where A is the cross-sectional area of the pipe and V is the

Ira Lisetskai [31]

For this case we have the following equation:
Q = Av
Where the area is given by:
A = pi * r ^ 2
A = pi * (d / 2) ^ 2
A = (pi / 4) * d ^ 2
Substituting we have:
Q = ((pi / 4) * d ^ 2) v
From here, we clear the diameter:
d = root ((4 / pi) * (Q / v))
Substituting values we have:
d = root ((4 / pi) * (50/600))
d = 0.36 feet
Answer:
The diameter of a pipe that allows a maximum flow of 50ft ^ 3 / min of water flowing at a velocity of 600ft / min is:
d = 0.36 feet

7 0

3 years ago

In a right triangle, the value of cos B = 3/5. What is the value of sin B?

Yanka [14]

Answer:It would be 3/5 as well.

Step-by-step explanation:

4 0

2 years ago

Consider the following system of equations:

monitta

Answer:

Step-by-step explanation: