- Midpoint formula is
.
<h3>19.</h3>
So starting with this one, we will be solving for the coordinates of the unknown endpoint separately. Starting with the x-coordinate, since we know that the midpoint x-coordinate is 5 and the x-coordinate of N is 2, our equation is set up as such:
From here we can solve for the x-coordinate of Q.
Firstly, multiply both sides by 2: 
Next, subtract both sides by 2 and your x-coordinate is 
With finding the y-coordinate, it's a similar process as with the x-coordinate except that we are using the y-coordinates of the midpoint and endpoint N.

<u>Putting it together, the missing endpoint is (8,4).</u>
<em>(The process is pretty much the same with the other problems, so I'll go through them real quickly.)</em>
<h3>20.</h3>


<u>The missing endpoint is (7,2).</u>
<h3>21.</h3>


<u>The missing endpoint is (-5,1).</u>
For this case we must solve the following system of equations:

To solve we follow the steps below:
We multiply the second equation by -3:

Thus, we have the equivalent system:

We add the equations:

We look for the value of the variable "y":

Thus, the solution of the system is given by:

Answer:

Answer:
linear
Step-by-step explanation:
The graph would be linear since it's .05 every minute, which would mean that every minute it would cost .05 --> adding up minutes. The flat fee at the beginning is trying to trick you up, don't get fooled ;)
Answer:
The last one 8
Step-by-step explanation:
The domain of a function f(x) is the set of all values for which the function is defined, and the range of the function is the set of all values that f takes. A rational function is a function of the form f(x)=p(x)q(x) , where p(x) and q(x) are polynomials and q(x)≠0 .