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kykrilka [37]
3 years ago
7

Determine if (-1,9) and (-2,6) are solutions to the system of equations: x + y = 8 x2 + y = 10 A) Both are solutions B) Neither

is a solution. C) It cannot be determined. D) Only (-1,9) is a solution.
Mathematics
1 answer:
Dahasolnce [82]3 years ago
7 0

Answer:

D) Only (-1,9) is a solution.

Step-by-step explanation:

x+y =8

x^2 + y = 10

Lets check the first point (-1,9)

Put in x =-1 y =9

x+y =8

-1+9 = 8

8 =8

This works

x^2 + y = 10

(-1)^2 +9 =10

1+9 = 10

10 = 10

This works

Lets check the second point (-2,6)

Put in x =-2 y =6

x+y =8

-2+6 = 8

4=8

This  does not work

We can stop now.  (-2,6) cannot be a solution

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If G is the circumcenter of triangle ABC, AG = 6x + 1, GC = 9x – 11, and BC = 38, find GF.
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Answer:

GF = 16.25

Step-by-step explanation:

If G is the circumcenter of triangle ABC, AG = 6x + 1, GC = 9x – 11, and BC = 38, find GF.

Step 1

We find x

AG = GC

6x + 1 =9x - 11

Collect like terms

1 + 11 = 9x - 6x

12 = 3x

x = 12/3

x = 4

Step 2

We solve for AG

GC = 9x + 11

GC = 9(4) + 11

GC = 36 + 11

GC = 25

Step 3

Solving for GF, using Pythagoras Theorem

GF² + BG² = GC²

GF² = GC² - BG²

GF = √GC² - BG²

GF = √25² - 19²

GF = √264

GF = 16.248076809

GF = 16.25

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