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katovenus [111]
3 years ago
10

ryan earns $5 for each small dog he walks and $8 for each latge dog he walks. today he walked 8 dogs and made a total of $55. ho

w many small dogs did ryan walk ?
Mathematics
1 answer:
ad-work [718]3 years ago
7 0

If we divide 55 (the total amount of money he made) by 5 (price to walk one small dog), we get 11. Meaning that the maximum amount of small dogs he could possibly walk and receive that amount of money is 11. However, he only walked 8 dogs. Therefore Ryan would have needed to walk a specific amount of large dogs in order to earn 55 dollars in total.

After doing some process of elimination, I reached this conclusion:

3 small dogs = $15

5 large dogs = $40

The combination of the two would equal $55.

Therefore, the answer would be 3 small dogs.

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Solve the equation X³+2X²-5X -6​
Natali [406]

Answer: x = {-1, -3, 2}

<u>Step-by-step explanation:</u>

x³ + 2x² - 5x - 6 = 0

Use the rational root theorem to find the possible roots:  ±1, ±2, ±3, ±6

Use Long division, Synthetic division, or plug them into the equation to see which root(s) work <em>(result in a remainder of zero)</em>.

I will use Synthetic division.  Let's try x = 1

1 |  1    2    -5     -6

  |<u>  ↓    1      3     -2 </u>      

     1     3    -2    -8   ← remainder ≠ 0 so x = 1 is NOT a root

 Let's try x = -1

- 1 |  1     2    -5    -6

   |<u>  ↓    -1     -1     6 </u>      

      1     1     -6     0   ← remainder = 0 so x = -1 is a root!

The coefficients of the reduced polynomial are: 1, 1, -6  -->   x² + x - 6

Factor: x² + x - 6

          (x + 3)(x - 2)

Set those factors equal to zero to solve for x:

x + 3 = 0   --> x = -3

x - 2 = 0    --> x = 2

Using Synthetic Division and Factoring the reduced polynomial, we found

x = -1, -3, and 2

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Sidana [21]
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Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

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