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Sonbull [250]
3 years ago
12

Solve a triangle with a = 25, b = 30, and C= 160°.

Mathematics
1 answer:
larisa86 [58]3 years ago
8 0

Answer:

a

Step-by-step explanation:

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Evaluate the following expression for x= 15. 1/5x-12
Mazyrski [523]

Step-by-step explanation:

1/5x-12=0

1/75-12=0

1-900=-899/75

ans=11.99

6 0
3 years ago
An economist uses the price of a gallon of milk as a measure of inflation. She finds that the average price is $3.82 per gallon
salantis [7]

Answer:

(a) The standard error of the mean in this experiment is $0.052.

(b) The probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c) The probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d) The likelihood that the sample mean is greater than $3.92 is 0.9726.

Step-by-step explanation:

According to the Central Limit Theorem if we have an unknown population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample mean is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample mean is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

n=40\\\mu=\$3.82\\\sigma=\$0.33

As <em>n</em> = 40 > 30, the distribution of sample mean is \bar X\sim N(3.82,\ 0.052^{2}).

(a)

The standard error is the standard deviation of the sampling distribution of sample mean.

Compute the standard deviation of the sampling distribution of sample mean as follows:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

    =\frac{0.33}{\sqrt{40}}\\\\=0.052178\\\\\approx 0.052

Thus, the standard error of the mean in this experiment is $0.052.

(b)

Compute the probability that the sample mean is between $3.78 and $3.86 as follows:

P(3.78

                               =P(-0.77

Thus, the probability that the sample mean is between $3.78 and $3.86 is 0.5587.

(c)

If the difference between the sample mean and the population mean is less than $0.01 then:

\bar X-\mu_{\bar x}

Compute the value of P(\bar X as follows:

P(\bar X

                    =P(Z

Thus, the probability that the difference between the sample mean and the population mean is less than $0.01 is 0.5754.

(d)

Compute the probability that the sample mean is greater than $3.92 as follows:

P(\bar X>3.92)=P(\frac{\bar X-\mu_{\bar x}}{\sigma_{\bar x}}>\frac{3.92-3.82}{0.052})

                    =P(Z

Thus, the likelihood that the sample mean is greater than $3.92 is 0.9726.

3 0
3 years ago
Alaina is selling wreaths and poinsettias for her chorus fundraiser. Wreaths cost $27 each poinsettia cost $20 each. If she sold
marishachu [46]

Answer:

The number of wreaths Alaina sells is 9 .

Step-by-step explanation:

As given

Alaina is selling wreaths and poinsettias for her chorus fundraiser.

Wreaths cost $27 each poinsettia cost $20 each.

If she sold 15 poinsettias and made $543.

Let us assume that the number of wreaths Alaina sells = x

As the number of poinsettias  Alaina sells = 15

Than the equation becomes

27x + 15 × 20 = 543

27x + 300 = 543

27x  = 543 - 300

27x  = 243

x = \frac{243}{27}

x = 9

Therefore the number of wreaths Alaina sells is 9 .

4 0
3 years ago
On a separate sheet of paper identify the indendepent and dependent variable for each table and graph.
BlackZzzverrR [31]

No hablo, lo siento, simplemente no puedo

8 0
3 years ago
Hew Sales data of an item, in 6'shops bf {after
skad [1K]

Answer:

xnuh and thought of it in a I have to do this but the free app on the app Store

5 0
3 years ago
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