1. You con solve the quadratic equation x^2+20x+100=50<span> by following the proccedure below:
2. Pass the number 50 from the right member to the left member. Then you obtain:
x^2+20x+100-50=0
</span><span> x^2+20x+50=0
</span><span>
3. Then, you must apply the quadratic equation, which is:
x=(-b±√(b^2-4ac))/2a
</span><span>x^2+20x+50=0
</span><span>
a=1
b=20
c=50
4. Therefore, when you substitute the values into the quadratic equation and simplify ir, you obtain that the result is:
-10</span>±5√2 (It is the last option).
Answer:
because x is the middle integer of three consecutive integers
=> The remaining 2 numbers respectively are x - 1 and x + 1
=> the sum of these three integers is
x - 1 + x + x + 1 = 3x
Is this a joke because it made me laugh
I’m pretty sure the answer is D. Sorry if I’m wrong
