Answer:
Part a) Daniel's age is 2 years
Part b) Kevin's age is 8 years
Step-by-step explanation:
<u><em>The question is </em></u>
Part a) How old is Daniel?
Part b) How old is Kevin?
Let
x ----> Kevin's age
y ----> Daniel's age
we know that
-----> equation A
----> equation B
Equate equation A and equation B
![4y=y+6](https://tex.z-dn.net/?f=4y%3Dy%2B6)
solve for y
![4y-y=6](https://tex.z-dn.net/?f=4y-y%3D6)
![3y=6](https://tex.z-dn.net/?f=3y%3D6)
![y=2](https://tex.z-dn.net/?f=y%3D2)
therefore
Daniel's age is 2 years
<em>Find the value of x</em>
substitute the value of y in any of the two equations
![x=4(2)=8\ years](https://tex.z-dn.net/?f=x%3D4%282%29%3D8%5C%20years)
![x=2+6=8\ years](https://tex.z-dn.net/?f=x%3D2%2B6%3D8%5C%20years)
therefore
Kevin's age is 8 years
Answer:
2.2.6
Step-by-step explanation:
Ok sweetheart, the easy way to solve these problems is to change them to all the same form for example "decimal" after that you sort them! just don't forget to remember which is which!!! so this is how you solve.
squared 25, 4.26, 3 1/5 2^3,2.58
i converted each so your answer is A.
You are multiplying by 10 each time so it is:
.02, 0.2, 2, 20, 200, 2000
XYR=36 hope this helps I actually don't know if it is right so I'm so sry if it is wrong so sry