Question

Need help lease!!!!!!!

Answer 1

(11)

the equation of a line in point- slope form is

y = mx + c ( m is the slope and c the y-intercept

thus y = 4x + 3 ← in slope-intercept form

the equation of a line in point- slope form is

y - b = m(x - a ) ( m is slope and (a, b ) a point on the line )

thus y - 3 = 4 ( x - 0 ) or y - 3 = 4x ← in point- slope form

the equation of a line in standard form is

Ax + By = C ( a is a positive integer and B, C are integers

rearrange y - 3 = 4x into this form

4x - y = - 3 ← in standard form

(12)

y = - 2x - 1 ← in slope-intercept form

y + 1 = - 2x ← in point- slope form

2x + y = - 1 ← in standard form