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3 years ago

Whoever answers first ill give Brainliest

Mathematics

1 answer:

fomenos3 years ago

6 0

I’m pretty sure the answer is 1/2 because if you look at the numbers: 3 is Half of 6 and 4 is half of 8. So the triangle shrunk by a half

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. Asking 100 students at a large university for their opinions on campus life is an example of measuring a _____.

Slav-nsk [51]

Answer:

Step-by-step explanation:

I am assuming that the university has much more than 100 students so 100 people is just a small sample.

3 0

3 years ago

Read 2 more answers

Answer please in less that 10 minutes

Andreyy89

Answer:

Step-by-step explanation:

Since we have an x under that radical, we have to get it out from under there. To do that, do the opposite of the square root, which is to square. But because this is an equation, you have to do the same thing to both sides. Doing this gives you

$6x-9=x^2$

Get everything on one side and set the quadratic equal to 0 and solve for x:

$x^2-6x+9=0$

Factor this into 2 factors of (x - 3)(x - 3) = 0. As you can see they are both the same, so x - 3 = 0 and x = 3. That's your answer. x = 3.

8 0

3 years ago

Problem 1 :

aleksley [76]

11 HOMES TO 8 AWAYS IS THE ANSWER

7 0

3 years ago

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Plz help fast reply plzzzz help

Reil [10]

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3 0

3 years ago

Write an equation of the line passing through the point (5, 1) that is perpendicular to the line 5x+3y=15. An equation of the li

pochemuha

Answer:

$\displaystyle y = \frac{3}{5}\, x + (-2)$ .

Step-by-step explanation:

The slope of a line in a plane would be $m$ if the equation of that line could be written in the slope-intercept form $y = m\, x + b$ for some constant $b$ .

Find the slope of the given line by rearranging its equation into the slope-intercept form.

$3\, y = (-5)\, x + 15$ .

$\displaystyle y = \frac{(-5)}{3} \, x + 5$ .

Thus, the slope of the given line would be $(-5) / 3$ .

Two lines in a plane are perpendicular to one another if and only if the product of their slopes is $(-1)$ .

Let $m_{1}$ and $m_{2}$ denote the slope of the given line and the slope of the line in question, respectively.

Since the two lines are perpendicular to each other, $m_{1}\, m_{2} = (-1)$ . Apply the fact that the slope of the given line is $m_{1} = (-5) / 3$ and solve for $m_{2}$ , the slope of the line in question.

$\begin{aligned}m_{2} &= \frac{(-1)}{m_{1}} \\ &= \frac{(-1)}{(-5) / 3} = \frac{3}{5}\end{aligned}$ .

In other words, the slope of the line perpendicular to $5\, x + 3\, y = 15$ would be $(3 / 5)$ .

If the slope of a line in a plane is $m$ , and that line goes through the point $(x_{0},\, y_{0})$ , the equation of that line in point-slope form would be:

$(y - y_{0}) = m\, (x - x_{0})$ .

Since the slope of the line in question is $(3 / 5)$ and that line goes through the point $(5,\, 1)$ , the equation of that line in point-slope form would be:

$\begin{aligned} (y - 1) = \frac{3}{5}\, (x - 5) \end{aligned}$ .

Rearrange this equation as the question requested:

$\begin{aligned} y - 1 = \frac{3}{5}\, x - 3 \end{aligned}$ .

$\begin{aligned} y = \frac{3}{5}\, x - 2 \end{aligned}$ .

$\begin{aligned} y = \frac{3}{5}\, x + (-2) \end{aligned}$ .

7 0

2 years ago