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Sladkaya [172]
3 years ago
10

What is the average of 104 and 67?

Mathematics
1 answer:
nirvana33 [79]3 years ago
5 0

Answer:

85.5

Step-by-step explanation:

104+67 / 2 = 85.5

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A bus travels 36 miles in 45 minutes. Enter the number of miles the bus travels in 60 minutes at this rate.
kompoz [17]

Answer:

The answer would be 48 miles in 60 minutes. I hope that helps!

Step-by-step explanation:

36 x 60 = 2160

45n = 2160

n = 48

8 0
3 years ago
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The perimeter of a football field is 920 feet. The width is 60 feet more than one-third of the length. What are the dimensions o
Step2247 [10]

Given:

Perimeter of a football field = 920 feet.

The width is 60 feet more than one-third of the length.

To find:

The dimensions of a football field.

Solution:

Let the length of the field be x.

Then, width = \dfrac{1}{3}x+60

We know that,

Perimeter = 2( length + width)

920 = 2(x+\dfrac{1}{3}x+60)

920 = 2(\dfrac{4}{3}x+60)

920 =\dfrac{8}{3}x+120

Subtract both sides by 120.

920-120 =\dfrac{8}{3}x+120-120

800 =\dfrac{8}{3}x

Multiply both sides by 3.

2400 =8x

Divide both sides by 8.

300 =x

Now,

Length = 300\text{ feet}

Width=\dfrac{1}{3}(300)+60

Width=100+60

Width=160\text{ feet}

Therefore, the length and width of the football field are 300 feet and 160 feet respectively.

7 0
3 years ago
Which graph is a function of x?
I am Lyosha [343]
Qt when you take the q and you take the t is makes the answer mate
5 0
4 years ago
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Angle MNO is formed by segments MN and NO on the following coordinate grid:
tekilochka [14]

Answer: m∠ M′N′O′ = 90 degrees

Step-by-step explanation: Hope that helps ! I am not sure if  I am right but I think I am !

3 0
3 years ago
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Help. I need help with these questions ( see image).<br> Please show workings.
Andrew [12]

9514 1404 393

Answer:

  4)  6x

  5)  2x +3

Step-by-step explanation:

We can work both these problems at once by finding an applicable rule.

  \text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}

where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.

This can be referred to as the <em>power rule</em>.

Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:

  lim[h→0](f(x+h)-f(x))/h = 2ax +b

__

4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.

5. The gradient of x^2 +3x +1 is 2x +3.

__

If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.

3 0
3 years ago
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