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inysia [295]
3 years ago
7

A track has the shapes shown. what is the perimeter ?

Mathematics
1 answer:
USPshnik [31]3 years ago
4 0
Break this problem down first. You have two lines each with length of 5. You also have two halves of a circle, combine them to get a full circle with a radius of 2. The formula to find the perimeter of a circle is
2\pi \times r
and this gives a perimeter of 12.566 for the circle. Add this to your sides and you get a total of 22.566 which is answer B
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Sum term product factor quotients coefficients for 5x+12
Svetllana [295]
I tried I hope this helps in any kind of way

4 0
3 years ago
I need help with this problem plzzz
Effectus [21]

Not sure sorry but you can. Try searching on google or yahoo answers

6 0
2 years ago
Someone please help!!! Can’t find this one anywhere!!! please and thank you!!!!!!!
Tema [17]

\dfrac{ 2+ 2i}{5+4i}\\\\\\=\dfrac{(2+2i)(5-4i)}{(5+4i)(5-4i)}\\\\\\=\dfrac{10-8i + 10i -8i^2}{5^2 -(4i)^2}\\\\\\=\dfrac{10+2i +8}{25+16}~~~~;[i^2 =-1]\\\\\\=\dfrac{18+2i}{41}\\\\\\=\dfrac{18}{41} + \dfrac{2}{41}i

4 0
2 years ago
If a point in the figure below is chosen at random, what is the probability that it is in the shaded region?​
Xelga [282]

Answer:

254/324 which is about 78.4%

Step-by-step explanation:

found area of entire square to be 18² or 324

found area of 4-quarter circles - which equals one circle with radius of 9

A = 81π which is about 70

subtracted 324 and 70 to get 254

ratio of shaded to unshaded is 254 : 324

3 0
2 years ago
Need help for question 8 and 9. I need the equation that’s passes through the points!
dsp73

Answer:

Step-by-step explanation:

Question 8

Let the equation of a line passing through two points (x_1,y_1) and (x_2,y_2) is given by,

y = mx + b

Here, m = slope and y-intercept = b

Since, m = \frac{y_2-y_1}{x_2-x_1}

For two points (1, 4) and (5, 8),

m = \frac{8-4}{5-1}

m = 1

Equation will be,

y = (1)x + b

y = x + b

Since, this line passes through (1, 4),

4 = 1 + b

b = 3

Therefore, equation of the line will be,

y = x + 3

Question 9

Let the equation is y = mx + b

m = \frac{y_2-y_1}{x_2-x_1}

For two points (2, 10) and (6, 4)

m = \frac{10-4}{2-6}

m = -\frac{3}{2}

By substituting the value of 'm' in the equation,

y = -\frac{3}{2}x+b

Since, this line passes through (2, 10)

10 = -\frac{3}{2}(2)+b

b = 10 + 2

b = 12

Therefore, equation of the line will be,

y=-\frac{3}{2}x+12

4 0
3 years ago
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