Answer:
Isamar
Step-by-step explanation:
We are given that a function
is a translation of the graph
Karla believes that the graph of g is '' to the right '' of the graph of f.
Isamar believes that the graph of g is ''to the left'' of the graph f.
When we draw a graph then we can see that
The coordinates of vertex of f are (0,0).
The coordinates of vertex of g(x) are (-3,0).
When x shift 3 units towards left then we get g(x)
Therefore, Isamar is correct.
Answer:
1. AC = 5 cm
2. CD = 10.7 cm
Step-by-step explanation:
Looking at the left triangle, we see that AC is the side "opposite" of the angle given and AB is the "hypotenuse".
Which trigonometric ratio relates "opposite" to "hypotenuse"?
<em>Yes, that's SINE.</em>
<em />
So we can write:
We know from 30-60-90 triangle, Sin(30) = 0.5, so we have:
Thus,
AC = 5 cm
Now, looking at right side triangle, we know AC, side "opposite" and we want to find CD, side "adjacent". Which trig ratio relates these 2 sides?
<em>Yes, that's tan!</em>
Thus we can write:
Now using calculator, we get our answer to be:
CD =
So
CD = 10.7 cm
Given: An Isosceles trapezoid EFGH in which EF =GH
To prove: ΔFHE ≅ ΔGEH
Proof: In Isosceles trapezoid EFGH, Considering two triangles ΔFHE and ΔGEH
1. FE ≅ G H → [ Given]
2. ∠H = ∠E
→ Draw GM⊥HE and FN ⊥EH, and In Δ GMH and ΔFNE,
GH=FE [Given]
∠M+∠N=180° so GM║FN and GF║EH, So GFMN is a rectangle.]
∴ GM =FN [opposite sides of rectangle]
∠GMH = ∠FNE [ Each being 90°]
Δ GMH ≅ ΔFNE [ Right hand side congruency]
→∠H =∠E [CPCT]
→ Side EH is common i.e EH ≅ EH .
→ΔFHE ≅ ΔGEH. [SAS]
