Answer:
2.50 + 5B ≤ 21;
Step-by-step explanation:
Cost of eggs = $2.50
Cost of avocado = $5 (bag of 3)
Total budgeted amount = $21
Bags of avocado = B
Therefore :
(Cost of eggs + cost of avocado) ≤ total budgeted amount
($2.50 + $5(B)) ≤ 21
2.50 + 5B ≤ 21
5B ≤ 21 - 2.50
5B ≤ 18.50
B ≤ 18.50 / 5
B ≤ 3.7
Therefore the maximum number of bags can purchase is 3(whole number without exceeding $21)
Answer: (2, -15)
Step-by-step explanation:
First 8 ten thousand
Second 8 thousand
Answer:
-8m+24-32n
Step-by-step explanation:
To expand this, we have to multiply -8 into m, -3, and 4n. Expanding, we get
(-8)(m)+(-8)(-3)+(-8)(4n)
This simplifies to
-8m+24-32n, which is our answer.
Distribute the 3 to the parentheses. Q=3r+3/r
Next multiply both sides by r to get rid of the division sign.
Qr=3r+3
Subtract 3r on both sides and you get Qr-3r=3
Since both numbers have an r in it, we can factor out the r
r(Q-3)=3
Then we divide Q-3 on both sides
r=3 / (Q-3)
