Question

At fly-right airlines, passengers are informed that checked bags must weigh 40 lb or less, or they will have to pay a fee for an oversized bag. (a) Write An inequality that represents the weight of a checked bag that will not result in a fee. Let w represent the weight of the bag. (b) Are there any solutions to the inequality that do not make sense for this situation? Explain answer

Answer 1

Given:

Checked bags must weigh 40 lb or less, or passengers will have to pay a fee for an oversized bag.

To Find:

An inequality that represents the weight of a checked bag that will not result in a fee and any solutions to the inequality that do not make sense for this situation.

Answer:

w ≤ 40 is the inequality representing the weight of a checked bag that will not result in a fee.

The only solutions to this inequality that may not make sense are if the weight of the bag is less than 0 lb (which is not possible) or even weighing exactly 0 lb (which is possible, but not practical).

Step-by-step explanation:

Let w denote the weight of the bag, as per the question.

Given that checked bags have to weigh 40lb or less, we have

w ≤ 40

that is, any checked bag has to weigh less than 40lb or 40lb exactly, to avoid paying the fee.

So, w ≤ 40 is the inequality representing the weight of a checked bag that will not result in a fee.

The only solutions to this inequality that may not make sense are if the weight of the bag is less than 0lb (i.e., in negative) as weight is a physical quantity that can only take positive values. Practically speaking, any checked bag will also not weigh exactly 0lb so, we can modify the above inequality to write

0 < w ≤ 40

Answer 2

Answer:

(a) $w\leq 40$.

(b) Negative values.

Step-by-step explanation:

(a)    

Let w be the weight of the bag.

We are told that at fly-right airlines, passengers are informed that checked bags must weigh 40 lb or less, or they will have to pay a fee for an over-sized bag. So the w must be less than or equal to 40 pounds.

We can represent this information in an inequality as: $w\leq 40$.

Therefore, the checked baggage with weight $w\leq 40$ will not result in a fee.

(b)  

Negative values do not make sense for this situation as weight of baggage can not be negative.

Therefore, negative weights as the solutions of the inequality do not make sense.