Question

Find the midpoint of the line segment whose endpoints are given (3/5 , -6/7),(2/5,5/7)

Answer 1

The formula of a midpoint between E and F:

$M_{EF}\left(\dfrac{x_E+x_F}{2};\ \dfrac{y_E+y_F}{2}\right)$

We have the points $\left(\dfrac{3}{5},\ -\dfrac{6}{7}\right)$ and $\left(\dfrac{2}{5},\ \dfrac{5}{7}\right)$. Substitute:

$\dfrac{\frac{3}{5}+\frac{2}{5}}{2}=\dfrac{\frac{5}{5}}{2}=\dfrac{1}{2}\\\\\dfrac{-\frac{6}{7}+\frac{5}{7}}{2}=\dfrac{-\frac{1}{7}}{2}=-\dfrac{1}{7}\cdot\dfrac{1}{2}=-\dfrac{1}{14}$

Answer: $\boxed{\left(\dfrac{1}{2},\ -\dfrac{1}{14}\right)}$