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BartSMP [9]
2 years ago
8

Label the missing side lenght of the figure khan academy

Mathematics
1 answer:
hammer [34]2 years ago
3 0

Answer:

i cant telll bc theres no picture

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Please help i am being timed i beg you please help
Viefleur [7K]
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6 0
2 years ago
Read 2 more answers
Solve for x: ( sqrt 7) ^ 6x = 49 ^ (x-6)
LiRa [457]
(\sqrt{7})^{6x}=49^{x-6} \\
(7^\frac{1}{2})^{6x}=(7^2)^{x-6} \\
7^{\frac{1}{2} \times 6x}=7^{2(x-6)} \\
7^{3x}=7^{2x-12} \\
3x=2x-12 \\
3x-2x=-12 \\
x=-12
8 0
2 years ago
Let f(x)=8x+8 find and simply f(x+1)
shusha [124]

Answer:

Step-by-step explanation:

f(x) = 8x + 8

f(x+1) = 8(x+1) + 8

= 8x + 8 + 8

= 8x + 16

8 0
2 years ago
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What number is six and four hundredths larger than two and five tenths?
Nostrana [21]

Answer:

eight and thirty-seven fiftyths

Step-by-step explanation:

6 and 4/100 + 2 and 5/10

6 and 1/25 + 2 and 1/2

156 / 25 + 5 / 2

312 / 50 + 125 / 50

437 / 50

400 / 50 = 8

8 and 37 / 50

7 0
2 years ago
Find the equations of the tangents to the curve x=9t2+3, y=6t3+3 that pass through the point (12,9).
Xelga [282]

Answer:

The equation will be "y=x-3".

Step-by-step explanation:

Given:

Points (12, 9) = (x, y)

⇒ x=9t^2+3

then,

 \frac{dy}{dt}=18t

or,

⇒ y=6t^3+3

then,

 \frac{dy}{dt}=18t^2

⇒ \frac{dy}{dx}=\frac{18t^2}{18t}

        =t

By using the point slope form.

The equation of tangent will be:

⇒ y-9=1(x-12)

   y-9=x-12

          y=x-12+9

          y=x-3

4 0
3 years ago
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