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mrs_skeptik [129]
4 years ago
12

How does knowing multiplication rules help solve problems faster and easier

Mathematics
2 answers:
Ivenika [448]4 years ago
8 0
I was about to say what the person said
KengaRu [80]4 years ago
3 0

Answer: It helps because you already know it off the top of your head and you are able to break up a multiplication problem step by step in your head.

Step-by-step explanation:

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Which tenths is 8.275 between
elena-s [515]

Answer:

8.3

Step-by-step explanation:

4 0
3 years ago
Help pls with answer!!!Rewrite the function in the given form.
Elis [28]

Answer:

g(x) = \frac{-2}{x-1}+5\\\\

The graph is shown below.

=========================================================

Explanation:

Notice that if we multiplied the denominator (x-1) by 5, then we get 5(x-1) = 5x-5.

This is close to 5x-7, except we're off by 2 units.

In other words,

5x-7 = (5x-5)-2

since -7 = -5-2

Based on that, we can then say,

g(x) = \frac{5x-7}{x-1}\\\\g(x) = \frac{5x-5-2}{x-1}\\\\g(x) = \frac{(5x-5)-2}{x-1}\\\\g(x) = \frac{5(x-1)-2}{x-1}\\\\g(x) = \frac{5(x-1)}{x-1}+\frac{-2}{x-1}\\\\g(x) = 5+\frac{-2}{x-1}\\\\g(x) = \frac{-2}{x-1}+5

This answer can be reached through alternative methods of polynomial long division or synthetic division (two related yet slightly different methods).

-------------------------

Compare the equation g(x) = \frac{-2}{x-1}+5\\\\ to the form g(x) = \frac{a}{x-h}+k\\\\

We can see that

  • a = -2
  • h = 1
  • k = 5

The vertical asymptote is x = 1, which is directly from the h = 1 value. If we tried plugging x = 1 into g(x), then we'll get a division by zero error. So this is why the vertical asymptote is located here.

The horizontal asymptote is y = 5, which is directly tied to the k = 5 value. As x gets infinitely large, then y = g(x) slowly approaches y = 5. We never actually arrive to this exact y value. Try plugging in g(x) = 5 and solving for x. You'll find that no solution for x exists.

The point (h,k) is the intersection of the horizontal and vertical asymptote. It's effectively the "center" of the hyperbola, so to speak.

The graph is shown below. Some points of interest on the hyperbola are

  • (-1,6)
  • (0,7) .... y intercept
  • (1.4, 0) .... x intercept
  • (2, 3)
  • (3, 4)

Another thing to notice is that this function is always increasing. This means as we move from left to right, the function curve goes uphill.

7 0
3 years ago
-x^6/125-y^3/64 plsssssssssssssssssssssssssssss help me
Marysya12 [62]

Answer:

-x^6/125-y^3/64

Step-by-step explanation:

that's what it Got

8 0
3 years ago
How do you factor 35x^2+26-16? Show work please.
Sedbober [7]

well, first off, we do a quick prime factoring of the leading term's coefficient, 35, and the constant, 16.

35 = 5*7

16 = 2*2*2*2

and the rest is just a mix and match.

what combination from the factors of 35 and the factors of 16, can provide a product whose sum is the middle term 26?  well, without further adieu.


we can try 5*2*2  + 7*2*2, and that's 20 and 28, ok, 28 - 20 is 8, so that won't work.

another can be 5*2*7  and 2*2, that's 70 and 4, 70 - 4 is 56, that won't work either.

5*2*2*2 and 7*2, that's 40 and 14, hmmm 40 - 14 = 26!!! holly guacamole!

so then,


\bf 35x^2+26x-16\implies (5x-\stackrel{\stackrel{2}{\downarrow }}{2})(7x+\stackrel{\stackrel{2\cdot 2\cdot 2}{\downarrow }}{8})

3 0
4 years ago
What is k^2 multiplied by y^2
dimaraw [331]
That would be (k^2 y^2), or simply (ky)^2 .
8 0
3 years ago
Read 2 more answers
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