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Whitepunk [10]
3 years ago
5

How do I do this problem

Mathematics
1 answer:
musickatia [10]3 years ago
4 0
What problem? There is no picture shown.
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Surface Area Math Question
sashaice [31]

Answer:

#ثوره_طلابية غاضبة على قرار وزاره التعليم العالي باصدارها القرار المجحف وعليه يبداء من الان الاعتصام الطلاب #والاضراب_عن_الدوام لحين تحقيق المطالب.

تعليم الكتروني = امــتـحـان الكتروني

تعليم حضوري = امــتـحـان حضوري

7 0
3 years ago
Please help!<br> both questions
BlackZzzverrR [31]
A)
f(2x)+g(3x-9)

2fx+g(3x)+g•-9

2fx+3gx+g•-9

Answer:2fz+3gz-9g



5 0
3 years ago
A random sample of the amounts for 22 purchases was taken. The mean was ​$42.97​, the standard deviation was ​$22.82​, and the m
Illusion [34]

Answer: a) 84 and b ) 2084

Step-by-step explanation:

Given : Sample standard deviation : s= $22.82

(Population standard deviation is unknown ) , so we use t-test.

Critical value or the​ 95% confidence intervals :t_{n-1}*=2.0

Formula to find the sample size :

n=(\dfrac{t^*\cdot s}{E})^2

a) E = 5

n=(\dfrac{(2)\cdot 22.82}{5})^2

n=(9.128)^2=83.320384\approx84

i.e. Required sample size : n= 84

b)  E = 1

n=(\dfrac{(2)\cdot 22.82}{1})^2

n=(45.64)^2=2083.0096\approx2084

i.e. Required sample size : n= 2084

8 0
3 years ago
Part A: Identify the point that is an x-intercept in order from left to right (1st)
zvonat [6]

Answer:

Using a Graph of a Line Identify the x-axis. A coordinate graph has a y-axis and an x-axis. The x …

Using the Equation of the Line Determine that the equation of the line is in standard form. The …

Using the Quadratic Formula Determine that the equation of the line is a quadratic equation. A

Step-by-step explanation:

3 0
3 years ago
Find the volume of the composite space figure to the nearest whole number.
Romashka [77]

Answer:

  d.  944 mm^3

Step-by-step explanation:

The area of a circle is given by ...

  A = πr² . . . . . where r is the radius, half the diameter

The area of a circle with diameter 9 mm is ...

  A = π(4.5 mm)² = 20.25π mm²

The area of the semi-circular end of the prism is half this value, or ...

  semicircle area = (1/2)(20.25π mm²) = 10.125π mm² ≈ 31.809 mm²

__

The area of the rectangular portion of the end of the prism is the product of its width and height:

  A = wh = (9 mm)(6 mm) = 54 mm²

Then the base area of the prism is ...

  base area = rectangle area + semicircle area

  = (54 mm²) +(31.809 mm²) = 85.809 mm²

__

This base area multiplied by the 11 mm length of the prism gives its volume:

  V = Bh = (85.809 mm²)(11 mm) ≈ 944 mm³

The volume of the composite figure is about 944 mm³.

7 0
3 years ago
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