Full Question
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t = 0, the resulting mass—spring system is disturbed from its rest state by the force F (t) = 20 cos(8t). The force F (t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Determine the spring constant k.
Answer:
Spring Constant = 1000Nm^-1
Step-by-step explanation:
Given
Mass = 10kg
Spring Extension = 9.8cm
Spring Constant K = Force/Extension
Force = Mass * Acceleration
Force = 10 * 9.8 = 9.8N
Spring Extension = 9.8 cm = 9.8 /100 = 0.098 m
Spring constant = 98 / 0.098
Spring Constant = 1000Nm^-1
Answer: 2
Step-by-step explanation: because it timed the seconde one so that is why its 2
hope the answer helped :)
Answer:
If im not wrong, just multiply wxlxh, for all sides, and you get 1260.
Step-by-step explanation:
I believe the answer is 75 I am not sure but I adds up because 4*.75 equals to 3 there is another way to solve this though we can do the is over of equals % over 100 then we still get three have a nice day and good luck on your assignment (:
Answer:
1. b.
2. a.
3. b.
4. d.
5. a.
6. b.
7. c.
8. b.
9. b.
10. c.
11. a.
12. b.
13. a.
14. c.
Step-by-step explanation:
7 + 3 = 10
+ 679 - 2056 = -1377
- 398 + 1 = -397
-23 - 237 = 260
2 - 6 = -4
-2 × 3 × -4 = 24
absolute value of -36 = 36
6 + 4 = 10
- 5928 - 965 = -6893
215 × 212 + 212 × 314 = 112148
(15 + 5) ÷ (15 + 5) = 20 ÷ 20 = 1
-457 + 1 = -456
- 218 -1 = -219
