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kobusy [5.1K]
3 years ago
6

Will give brainliest please help ASAP

Mathematics
1 answer:
marissa [1.9K]3 years ago
7 0

Answer: 1) If we talk about whole numbers then we should choose only square numbers that could be the area of square so that if we want to find its  side so we a can find its square root i.e. side.

2) We can find the square root of the area of the given square to find the side length of the square.

3) No , it is not possible to find a side length that would be perfect for a square with an area of 45 square units because if we find its side we need to find its square root i.e.

side=\sqrt{45}=\sqrt{3\times3\times5}=3 \sqrt{5}................>which is irrational and √5=2.236

∴side=3×2.236=6.708 unit ......> which is not accurate we need to take approx value of it to get the side length of the square.



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Leokris [45]

where is the figures to solve.

4 0
3 years ago
Find the total number of diagonals in a regular nonagon.
anastassius [24]

Answer:

7

Step-by-step explanation:

number of diagonals in a regular polygon = number of sides - 2.

A nonagon is a polygon having 9 sides.

Total number of diagonals in a regular nonagon

= 9 - 2

= 7

3 0
3 years ago
A food company sells salmon to various customers. The mean weight of the salmon is 37 lb with a standard deviation of 2 lbs. The
brilliants [131]

Answer:

The standard deviation for the mean weigth of Salmon is 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount order stores.

Step-by-step explanation:

The mean sample of the sum of n random variables is

\overline{X} = \frac{X_1+X_2+...+X_n}{n}

If X_1, ..., X_n are indentically distributed and independent, like in the situation of the problem, then the variance of X_1 + .... + X_n will be the sum of the variances, in other words, it will be n times the variance of X_1 .

However if we multiply this mean by 1/n (in other words, divide by n), then we have to divide the variance by 1/n², thus \overkine{X} = \frac{V(X_1)}{n} and as a result, the standard deviation of \overline{X} is the standard deviation of X_1 divided by \sqrt{n} .

Since the standard deviation of the weigth of a Salmon is 2 lbs, then the standard deviations for the mean weigth will be:

  • Restaurants: We have boxes with 9 salmon each, so it will be \frac{2}{\sqrt{9}} = \frac{2}{3}
  • Grocery stores: Each carton has 49 salmon, thus the standard deviation is \frac{2}{\sqrt{49}} = \frac{2}{7}
  • Discount outlet stores: Each pallet has 64 salmon, as a result, the standard deviation is \frac{2}{\sqrt{64}} = \frac{1}{4}

We conclude that de standard deivation of the mean weigth of salmon of the types of shipment given is: 2/3 lbs for restaurants, 2/7 lbs for grocery stores and 1/4 lbs for discount outlet stores.

7 0
3 years ago
You charge people $10 per hour to pick fruits and $8 per hour
Aleks04 [339]
Fruits :
Y=10(h)

Flowers;
Y=8(h)

Given: h=6

Fruits:
10(6) = $60

Flowers:
8(6)= $48

Back to the question, how much more from picking fruits?

$60 - $48 = $12 more picking fruits.

Hope this helps!

8 0
3 years ago
Drag the ordered pair that are 5.5 units apart.
Alexus [3.1K]

Answer:

  (-1.5, -3.5) and (-1.5, 2)

Step-by-step explanation:

The x-coordinates in increasing order are ...

  -3, -1.5, 5

The distances between pairs of these coordinates are ...

  -1.5 -(-3) = 1.5

  5 -(-3) = 8

  5 -(-1.5) = 6.5

Clearly, any pair with x = 5 is too far away from any pair with a different x-value.

<u>∆x = 1.5</u>

If the distance between pairs is 5.5, then the distance formula tells us the y-coordinate differences for pairs with x-coordinates of -3 and -1.5 must be ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  5.5 = √(1.5^2 +(y2 -y1)^2) . . . substitute known values

  30.25 = 2.25 +(y2 -y1)^2 . . . . square both sides

  √28 = (y2 -y1) . . . . . . . . . . . . . . subtract 2.25 and take the square root

This value is irrational. Clearly none of the y-coordinates is irrational, so there are no point pairs with x-coordinates -3 and -1.5 that are 5.5 units apart.

__

<u>∆x = 0</u>

If the x-coordinates are the same, then the y-coordinates must differ by 5.5 in order for the points to be 5.5 units apart. The coordinates in order are ...

  for x = -1.5, y = -3.5, 2, 2.5 . . . . . differences of 5.5, 6, 0.25

  for x = 5, y = -3.5, 1.5 . . . . . . . difference of 5

The only pair we can find that is 5.5 units apart is ...

  (-1.5, -3.5) and (-1.5, 2).

6 0
2 years ago
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